(2m²n 3pq² )(5p²q 4mn ) (5mnp 3q)
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39522718:(m+n)²-2(m+n)(p+q)-15(p+q)=[(m+n)-5(p+q)][(m+n)+3(p+q)]=(m+n-5p-5q)(m+n+3p+3q)因式分解吧?解析
3p=5qp=5q/32p-3q=110q/3-3q=11/3q=1q=1/3q=5/9
原式=p^2-2pq+q^2-4(p-q)-5=(p-q)^2-4(p-q)-5=(p-q-2)^2-9=(p-q+1)(p-q-5)
M=P+Q={1,2,6,3,4,8,6,7,11}={1,2,3,4,6,7,8,11}M的子集个数=2^8=256#
再答:再问:你数错了再问:14x2=?你说呢再答:14乘3好么!!!!!再答:12乘3等于36好么!再问:哪有再问:对再问:你回答对了,我看错了再问:对不起再答:没事啦~再答:采纳啊亲再问:恩再答:采
1.6q-17p-2p-3q2.49-4a-4
=(2p²-pq+4pq-2q²)-(p²-q²)=p²+3pq-q²
(2m2;n/3pq2;)(5p2;q/4mn)/(5mnp/3q)=(m/3q)(5p/2)/(5mnp/3q)=(5pm/6q)/(5mnp/3q)(颠倒相乘)=(5pm/6q)(3q/
m²(p-q)-p+q=m²(p-q)-(p-q)=(m²-1)(p-q)=(m+1)(m-1)(p-q)
(m+n+p-q)(m-n-p-q)=[(m-q)+(n+p)][(m-q)-(n+p)]=(m-q)^2-(n+p)^2=.下面你应该算了吧,O(∩_∩)O哈哈~这道题目需要我们掌握的是每两项在一起
4Q+P=2P-24Q-P--24P=-(5-3Q)3Q-4P=5Q=-1P=-2Y对称4Q+P=-(2P-2)4Q+3P=24P=5-3QQ=-25/7P=26/25原点对称4Q+P=-(2P-2)
4Q+P=2P-24Q-P--24P=-(5-3Q)3Q-4P=5Q=-1P=-2Y对称4Q+P=-(2P-2)4Q+3P=24P=5-3QQ=-25/7P=26/25原点对称4Q+P=-(2P-2)
(2m²n/3pq²)(5p²q/4mn)/(5mnp/3q)=(m/3q)(5p/2)/(5mnp/3q)=(5pm/6q)/(5mnp/3q)(颠倒相乘)=(5pm/
解题思路:本题考查一元二次方程的配方过程,从配方过程的具体形式进行分析可得p与q的值。解题过程:解法一:比较两个方程x2-4x+q=0及x2-4x+q=2可发现第一个方程的右边加2得到第二个方程那么配
关于x轴对称的两点,横坐标相等,纵坐标互为相反数,则4p=5-3p,4q+p=-(2p-2)解得p=5/7,q=-1/28.关于y轴对称,则纵坐标相等,横坐标互为相反数,则-4p=5-3p,4q+p=
(m+n)(p+q)-(m+n)(p-q)=(m+n)(p+q-P+q)=(m+n)×2q=2q(m+n)
M-2N=(12p+3q)-2(-3q-5p)=12p+3q+6q+10p=22p+9q
∵P-Q+Q=3m2-2m-5+2m2-3m-2=5m2-5m-7,∴P+Q=5m2-5m-7+2m2-3m-2=7m2-8m-9,或直接计算P-Q+2Q得P+Q也可.
(1)6p(p+q)-4q(p+q)=(6p-4q)(p+q)=2(3p-2q)(p+q)(2)2ab(m-2n)+4b(2n-m)=2ab(m-2n)-4b(m-2n)=ab(a-2)(m-2n)(