(7.4m÷2)²×3.14
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 00:31:41
![(7.4m÷2)²×3.14](/uploads/image/f/12800-56-0.jpg?t=%287.4m%C3%B72%29%C2%B2%C3%973.14)
[(m-2)/(m+2)+4m/(m²-4)]÷[1/(4-m²)]=[(m-2)²+4m]/(m+2)(m-2)×(2-m)(2+m)=-(m²-4m+4+4
(m^2-n^2/mn)^2÷(m+n)^2*(m/m-n)^3=(m+n)^2(m-n)^2/m^2n^2÷(m+n)^2*m^3/(m-n)^3=(m-n)^2/m^2n^2*m^3/(m-n)^
(m/m+3-2m/m+3)÷m/m^-9=(m-2m)/(m+3)÷m/(m+3)(m-3)=-m÷m/(m-3)=3-m如果本题有什么不明白可以追问,
[5(m+n)2(m-n)]3÷【3(m+n)2(n-m)]2=125(m+n)的6次方(m-n)³÷9(m+n)的4次方(m-n)²=125/9(m+n)²(m-n)如
原式=-(m-3)/2(m-2)÷[(m+2)(m-2)-5]/(m-2)=-(m-3)/2(m-2)÷(m²-9)/(m-2)=-(m-3)/2(m-2)×(m-2)/(m+3)(m-3)
=[(m^2-4)/(m-2)]/(m+2)=(m+2)/(m+2)=1
(m+2/m²-2m)-(m-1/m²-4m+4)÷(m-1/m)=(m+2)/m(m-2)-(m-1)/(m-2)^2*m/(m-1)=(m+2)/m(m-2)-m/(m-2)^
[(-m)^2]^8÷(-m*m^3)÷(-m^2)^3=(m^2)^8÷(-m^4)÷[-m^(2*3)]=m^(2*8)÷(-m^4)÷[-m^(2*3)]=m^16÷m^4÷m^6=m^(16+
m^2-m/m^2-1÷m/m-1乘(m+1/m-1)^2=m(m-1)/(m+1)(m-1)*(m-1)/m*(m+1)²/(m-1)²=(m+1)/(m-1)
带入可得(9+6+1/9-1+9+1)*(-2)=-434/9再问:能写一下过程吗?再答:带入得(9+6+1/9-1+9+1)÷(1-3/2)=(24+1/9)÷(-1/2)=(217/9)×(-2)
(m-3)/(m平方-1)÷(m平方-3m)/(m平方+2m+1)-1/(m-1)=(m-3)/(m-1)(m+1)×(m+1)²/m(m-3)-1/(m-1)=(m+1)/m(m-1)-m
1.5^m*125^m÷25^(2m-1)=5^m*5^(3m)÷5^(4m-2)=5^(m+3m-4m+2)=252.5/8[(a+b)(a-b)]^4*4/9(a+b)^4(b-a)^5=5/18
=(m-2)²/(m+1)(m-1)*(m+1)/m-2+2/m-1=(m-2)/(m-1)+2/m-1=m/m-1=2
原式=(m-1)²/(m+1)(m-1)÷[(m-1)-(m+1)²]/(m+1)=(m-1)/(m+1)×(m+1)/(-m²-m-2)=-(m-1)/(m²
原式=-(m+4)(m-4)/(m+4)²×2(m+4)/(m-4)×(m-2)/(m+2)=-(m-4)/(m+4)×2(m+4)/(m-4)×(m-2)/(m+2)=-2×(m-2)/(
证明:因为,m∈M,n∈M所以m=a+b√2,n=,c+d√2,其中a,b,c,d∈Q,m+n=(a+c)+(b+d)√2,因为a+c∈Q,b+d∈Q,所以m+n∈M.m-n=(a-c)+(b-d)√
1÷1+m/1-m·(m²-1)=(1-m)/(1+m)*(m+1)(m-1)=-(m-1)²=-m²+2m-1选2如果本题有什么不明白可以追问,