从控制台输出3个数字a,b,c,用逻辑运算符判断下a是否是最大值

#include"stdio.h"main(){intA,B,C,min;printf("inputA,B,C:");scanf("%d%d%d",&A,&B,&C);min=A;if(min>B){

2a=3c,a=3/2c3c=4b,b=3/4ca+c+b+b=400即3/2c+c+2*(3/4c)=400c=100a=150,b=75,c=100

#include "stdio.h"int gcd(int x,int y)    //欧几里得辗转

voidmain(){doublea,b,c;scanf("%lf%lf",&a,&b);c=a*a+b*b;if(c>100)printf("a^2+b^2=%lf\n",c);elseprintf

Reverse

这种返回方式,我没有用过,但是先以你的doublex这个函数做个比方doublex(doublex,doubley,doublez){doublex1,x2;x1=(-y-sqrt(pow(y,2)-

给你个c语言的,#includeintmain(){longinta,b,c,t;printf("输入数据\n");scanf("%d%d%d",&a,&b,&c);if(a>b){t=a;a=b;b

#include"stdio.h"#defineN6voidmain(){inti,j,k;for(i=1;i

//Note:YourchoiceisC++IDE#includeusingnamespacestd;longintSfun(constintN){longintsum=1;if(N==0||N==1

#includeintmain(void){intnum,hundred,ten,indiv;printf("请输入一个三位整数:");scanf("%d",&num);hundred=num/100

#include"stdio.h"voidmain(){inta,b,c,d,t;printf("输入四个整数");scanf("%d%d%d%d",&a,&b,&c,&d);if(a{t=a;a=b

页面代码请输入第一个数：请输入第二个数：请输入第三个数：计算三个数中最小的数是：js代码是functiongetnum(){varnumone=document.getElementById("tex

#includevoidmain(){inta,b,c;intm;printf("Pleaseinputabc\n");scanf("%d%d%d",&a,&b,&c);m=a;if(b>m)m=b;

#include"stdio.h"#include"math.h"main(){inta,b,i,j,k,t,n=0;printf("请输入两个整数:");scanf("%d%d",&a,&b);if

不用数组的方法：#includeusingnamespacestd;voidmain(){inta,b,c,d;intt;couta>>b>>c>>d;if(a{t=a;a=b;b=t;}if(a{t

DimiAsLong,jAsLong,kAsLongFori=1To20Forj=iTo20Fork=jTo20Ifi^2+j^2=k^2ThenPrinti;j;kNextkNextjNexti所有

importjava.util.Scanner;publicclassDemo{publicstaticvoidmain(String[]args){intx=newScanner(System.in

数学必修三上不是有的吗?

#includeintmain(){inta,b,c;printf("Pleaesinput3int:");scanf("%d%d%d",&a,&b,&c);a=(a>=b)?a:b;a=(a>=c)

#includevoidmain(){inta,b,c;printf("输入三个数：");scanf("%d%d%d",&a,&b,&c);if(a>b&&a>c)printf("最大值为：%d",a