从键盘输入两个整数m和n,编程计算并输出最大值.输入mn 输出mn的最大值,
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![从键盘输入两个整数m和n,编程计算并输出最大值.输入mn 输出mn的最大值,](/uploads/image/f/1779371-35-1.jpg?t=%E4%BB%8E%E9%94%AE%E7%9B%98%E8%BE%93%E5%85%A5%E4%B8%A4%E4%B8%AA%E6%95%B4%E6%95%B0m%E5%92%8Cn%2C%E7%BC%96%E7%A8%8B%E8%AE%A1%E7%AE%97%E5%B9%B6%E8%BE%93%E5%87%BA%E6%9C%80%E5%A4%A7%E5%80%BC.%E8%BE%93%E5%85%A5mn+%E8%BE%93%E5%87%BAmn%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%2C)
importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System
#includemain(){intm,n,k,j,s,t;printf("pleaseinputthenumberofm,n,k\n");scanf("%d",&m);scanf("%d",&n);
#includeusingnamespacestd;intmain(){inti,n,s=0;coutn;s=0;for(i=1;i
主函数这样intmain(){intsum=0;inti;intn;printf("Pleaseinputanumber:");scanf("%d",&n);for(i=1;i
#includevoidmain(){\x09intnum[100];\x09inti;\x09for(i=0;i
#includevoidmain(){intm,n,r,x;scanf("%d,%d",&m,&n);x=m*n;while(n!=0){r=m%n;m=n;n=r;}printf("%d%d\n",
#include "stdio.h"int main(){ int count1=0,count2=0,i;&nbs
楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)
#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09a=a+b;\x09b=a-b;\x09a=a-b;\x09printf("%d%d"
//m与n的值不能太大,且用空格分隔.如:53#includeintfun(intn){\x09if(n==0||n==1)return1;\x09elsereturnn*fun(n-1);}void
#includeintmain(){intm,n;intsum1=0,sum2=0;scanf("%d%d",&m,&n);for(inti=m;i
#include#includeusingnamespacestd;boolprime(intn){\x09for(inti=2;in;\x09cout
#include#includevoidmain(){intn,s,j,i;printf("inputn(n
最大公约数:intGcd(inta,intb){if(a%b==0)returna;return(b,a%b);}最小公倍数:intGbs(inta,intb){returna*b/Gcd(a,b);
importjava.util.*;publicclassCombination{publicstaticvoidmain(String[]args){VectortestData=newVector
inta,b,max;scanf("%d",&a);scanf("%d",&b);max=Max(a,b);intMax(inta,intb){returna>b?a:b;}再问:确定吗这个答案?再答
clearinput"请输入第1个数:"toainput"请输入第2个数:"tobc=max(a,b)dowhile.t.ifc%a=0andc%b=0s=cexitendifc=c+1enddo"它
#includevoidprint(intspace,intnum,inttype){while(space--)putchar('');if(type){while(num--)putch
给你个可以加减乘除的!#includevoidmain(){floata,b;charc;printf("\n");scanf("%f%c%f",&a,&c,&b);if(c=='+')