关于xy的多项式,6mx的2次方 4nxy 2x 2xy-x的2次方 y 4
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![关于xy的多项式,6mx的2次方 4nxy 2x 2xy-x的2次方 y 4](/uploads/image/f/2140937-17-7.jpg?t=%E5%85%B3%E4%BA%8Exy%E7%9A%84%E5%A4%9A%E9%A1%B9%E5%BC%8F%2C6mx%E7%9A%842%E6%AC%A1%E6%96%B9+4nxy+2x+2xy-x%E7%9A%842%E6%AC%A1%E6%96%B9+y+4)
要使关于字母x,y的多项式mx³+3nxy²+2x³-xy²+y不含3次项,m+2=0m=-23n-1=0n=1/32m+3n的值=-4+1=-3
45再问:过程是什么再答:难写再问:拜托了再答:这是几年级的题目?再问:初一再答:图片发得慢再答:
mx^3+3nxy^2+2x^3-xy^2+y=(m+2)x^3+(3n-1)xy^2+ym+2=0,3n-1=0m=-2,n=1/32m+3n=-4+1=-3
根据题意4n+2=02n=-16m-1=06m=16m-2n+2=1+1+2=4
不含3次项说明三次项系数为0原式=(m-2)x^3+(3n-1)xy^2+y所以m-2=0,3n-1=0m=2,n=1/32m+3n=4+1=5
多项式为:(n+2)x^2y^(m-1)+xy^2-3x^2-6.因为多项式是6次多项式,所以:m-1=6-2,即m=5.系数n+2≠0,即m≠-2.
6mx²+4nxy+2x+2xy-x²+y+4=(6m-1)x²+(4n+2)xy+2x+y+4前两项是二次项所以他们的系数是06m-1=0.4n+2=06m=1,2n=
mx^2+2xy-x与3x^2+nxy+3y的差=(m-3)x²+(2-n)xy-x-3y不含二次项,则m-3=0,2-n=0则m=3,n=2则n^m=2³=8
mx^2+2xy-x-(3x^2+nxy-3y)=mx^2+2xy-x-3x^2-nxy+3y=(m-3)x^2+(2-n)xy+3y二次项有x^2,xy,不含二次项表示二次项前的系数是0所以m-3=
6mx^2+4nxy+2x+2xy-x^2+y+4=6mx^2-x^2+4nxy+2xy+2x+y+4=(6m-1)x^2+(4n+2)xy+2x+y+4不含二次项,即6m-1=0,m=1/64n+2
mx^2+2xy-x-(3x^3-2nxy+3y)=-3x^3+mx^2+(2+2n)xy-3y-x上式不含二次项,则二次项系数为0.m=02+2n=0n=-1n^m=1
解mx³-3nxy²-2x³-xy²-y=(mx³-2x³)-(3nxy²+xy²)-y=(m-2)x³-(3
由题意得:相同的2次项的系数为0,即-a+1=0-2b-2=0所以a=1b=-1所以5a-8b=5×1-8×(-1)=5+8=13
mx^2+2xy-x-(3x^2-2nxy+3y)=mx^2+2xy-x-3x^2+2nxy-3y=(m-3)x^2+(2+2n)xy-x-3y因为不含二次项,则m-3=02+2n=0m=3n=-1
2mx^3+3nxy^2+5x^3-xy^2+y=(2m+5)x^3+(3n-1)xy^2+y不含3次项2m+5=0,3n-1=02m=-5,3n=12m+3n=-5+1=-4
依题目意得6m=14n=-2,即2n=-12m²n+10m-4n+2-2m²n-4m+2n=6m-2n=1-(-1)=2再问:可以给我分析一下题目吗,我不是很明白。谢谢再答:因为多
∵mx²+2nxy-x+x²-2xy+y=(m+1)x²+(2n-2)xy-x+y结果中不含2次项,则m+1=0,2n-2=0∴m=-1,n=1∴3m-2n=3×(-1)
6m=14n+2=0m=1/6;n=-1/26m-2n+2=4
=(m-3)x³+(2+2n)xy-x-3y更改为合并后不含二、三次项或x是二次的∴m-3=02+2n=0∴m=3n=-1n^m=(-1)³=-1再问:呀?对不起!!!偶打错啦。。
(mx²+2xy-x)-(3x²-2nxy+3y)=mx²+2xy-x-3x²+2nxy-3y=(m-3)x²+(2+2n)xy-x-3y不含二次项则