分解因式x^2 xy-2y^2=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/09 13:39:23
先把括号化简去掉,注意去扩前的加减号,加号去括号不变号,减号去括号要变号,8(x^2-2y^2)-x(7x+y)+xy=8X^2-16y^2-7x^2-xy+xy排列一下化简后因式的顺序,8x^2-7
x²-3x²y-3xy²-y²(这里应该少了²)=(x+y)(x-y)-3xy(x+y)=(x+y)(x-y-3xy)
(1-x^2)(1-y^2)+4xy=1-x²-y²+x²y²+4xy=(x²y²+2xy+1)-(x²-2xy+y²)
壹点丶dream:-2xy-x²-y²=-(2xy+x²+y²)=-(x+y)²
2xy+9-x^2-y^2=9-x^2-y^2+2xy=9-(x^2+y^2-2xy)=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)
2.6x²-13xy+6y²+22x-23y+20=(2x-3y)(3x-2y)+22x-23y+4×5=(2x-3y+4)(3x-2y+5)3.(x²+4x+8)
解2x²y-x³-xy²=x(2xy-x²-y²)=-x(x²-2xy+y²)=-x(x-y)²
x^2-6xy+9y^2-2x+6y=(x^2-6xy+9y^2)-(2x-6y)=(x-3y)^3-2(x-3y)=(x-3y)(x-3y-2)
12x^2+xy-6y^2=(4x+3y)(3x-2y)
4x²+2xy-2y²+4x+7y-3=(2x-y+3)(2x+2y-1)因为4x²+2xy-2y²=(2x-y)(2x+2y)所以设4x²+2xy-
x²-2xy+y²-2x+2y+1=(x-y)^2-2(x-y)+1=(x-y-1)^2
原式=8x^2-16y^2-7x^2-xy+xy=x^2-16y^2=(x+4y)(x-4y).
是不是x^3y+x^2y+2xy^2-4xy^3原式=xy(x^2-4y^2)+x^2y+2xy^2=xy(x+2y)(x-2y)+xy(x+2y)=xy(x+2y)(x-2y+1)
这个题目看结构,应该是出错了,好像应该是(x^2-2xy)^2+2y^2(x^2-2xy)+y^4只有这样,才能形成完全平方公式(x^2-2xy)^2+2y^2(x^2-2xy)+y^4=(x^2-2
x²+2xy+y²-1=(x+y)²-1=(x+y+1)(x+y-1)
你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=(x-y/2)^2+3y^2/4恒大于0,无法分解
授人以鱼不如教人以渔,解这样的题关键还是要有思路,不能向上面的人只给答案,将来你还是会遇到问题.思路如下:-2x²y-12xy²+8xy³=xy(8y^2-2x-12y)
9-x^2+2xy-y^2=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)
原式=(x+y)(x+y)+2(x+y)xy+(xy)^2-1^2=(x+y)^2+2(x+y)xy+(xy)^2-1=(x+y+xy)^2-1=(x+y+xy-1)(x+y+xy+1)=(x+y+x
x^2-2xy+y^2-9=(x-y)^2-9=(x-y+3)(x-y-3)