化简求值x-1分之x2加1-x分之2x的和除以x-1分之x-搜答案-搜搜考试网

[3x/(x-1)-x/(x+1)]÷x/(x²-1)=[3x/(x-1)-x/(x+1)]*(x²-1)/x=[3x/(x-1)]*(x²-1)/x-[x/(x+1)]

解x²-3x+1=0两边除以x得：x-3+1/x=0即x+1/x=3两边平方得：(x+1/x)²=9即x²+2+1/x²=9∴x²+1/x²

方程两边同时乘以x(x+1)(x-1)得：5(x-1)+3(x+1)=7x解得：x=2检验：x(x+1)(x-1)=6所以x=2是原分式方程的解

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

原式=[3x/(x-1)-2x/(x+1)]*(x+1)(x-1)/x=3x/(x-1)*(x+1)(x-1)/x-2x/(x+1)*(x+1)(x-1)/x=3(x+1)-2(x-1)=3x+3-2

x²+2x+1=10（x+1)²=10x+1=3或x+1=-3所以x=2或x=-4【（x²+4)/x-4】÷【（x²-4)/(x²+2x)】=【（x&

原式=(x-1)(x+1)/(x+2)*(x+2)/x-1=x+1然后代入数值即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

(x^2-2x+1)/(x^2-1)+1/(x+1)=(x-1)^2/(x+1)(x-1)+1/(x+1)=(x-1)/(x+1)+1/(x+1)=x/(x+1)=1-根2分之一

=1/(x+2)-(x+1)²/(x+2)×(x-1)/(x+1)(x-1)=1/(x+2)-(x+1)/(x+2)=-x/(x+2)当x=√2-2时原式=（2-√2)/√2=√2-1

{1-x/(x-1)}÷1/x(x-1)=(x-1-x)/(x-1)÷1/x(x-1)=-1/(x-1)÷1/x(x-1)=-x

把一个整体的加上括号后再发出来,你的这个实在分不清没法帮忙啊.再问：化简求值（x/x-1）-（x3/x∧2-1）x（x∧22x1/x3）其中x=√21这样可以吗？再答：我描述下吧你看看是不是x/x-1

详细而规范的解答过程看图,明白就采纳,

原式=2x²-4x²+3x-3x+7+1=-2x²+8=-2*2²+8=-8+8=0

X2/X2-1÷(1-2X/X-1-X+1)＝X^2/(x^2-1)÷[(1-2x)/(x-1)-(x-1)]=x^2/(x^2-1)÷[(1-2x-(x^2-2x+1)/(x-1)]=x^2/(x+

[（x+2)/x-(x-1)/(x-2)]÷（x-4)/x=[1+2/x-1-1/(x-2)]×x/(x-4)=(x-4)/x(x-2)×x/(x-4)=1/(x-2)=1/(3-2)=1这是我在静心

原式=(x+1)/(x+1)²×x(x-1)/[-2(x-1)]=-1/(x+1)×x/2=-x/2(x+1)当x=√2时原式=-√2/2(√2+1)=-√2(√2-1)/2=(√2-2)/

--2分之1(xy--x^2)+3(y^2--2分之1x^2)+2(4分之1xy--2分之1y^2)=--xy/2+x^2/2+3y^2--3x^2/2+xy/2--y^2=--x^2+2y^2,当x

(x+1分之1+x-1分之1)·(x平方-1)=x+1分之1·(x平方-1)+x-1分之1·(x平方-1)=x-1+x+1=2x