2x 3y-4=04的x方*8的y次方
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∵|2x-3y+1|+(x+3y+5)的二次方=0∴2x-3y+1=0x+3y+5=0x=-2y=-1∴(-2x*y)的二次方(-y的二次方)×6xy平方的值=4x⁴y*(-y²
x3y+2x2y2+xy3=xy(x2+2xy+y2)=xy(x+y)2,∵x+y=5,∴(x+y)2=25,x2+y2+2xy=25,∵x2+y2=13,∴xy=6,∴xy(x+y)2=6×25=1
反应前XY均为0价,反应后化合价有变化,四氧化还原反应.提一句,4X2+Y2=X3Y+Y2去掉Y2的话是4X2=X3Y,这是不可能的,元素本身发生了变化,应该是核反应
∵x+y=4,∴(x+y)2=16,∴x2+y2+2xy=16,而x2+y2=14,∴xy=1,∴x3y-2x2y2+xy3=xy(x2-2xy+y2)=14-2=12.
原式=x4+x3y+4x3y+x2y+4x2y2+4x2y2+xy2+4xy3+xy3+y4,=x3(x+y)+4x2y(x+y)+xy(x+y)+4xy2(x+y)+y3(x+y),=-x3-4x2
X方-2x+1=9X方-2x-8=0(x-4)(x+2)=0x1=4,x2=-24X方+4X+1=2(2X+1)方=22x+1=根2或-根2x1=(根2-1)/2,x2=-(根2+1)/2五分之二X方
(2x4-4x3y-x2y2)-2(x4-2x3y-y3)+x2y2=2x4-4x3y-x2y2-2x4+4x3y+2y3+x2y2=2y3,因为化简的结果中不含x,所以原式的值与x值无关.
原式=8x^5y²/(-2x²y)-4x²y^5/(-2x²y)=-4x³y+2y³
原式=(x^4-2x²y²+y^4)+6xy(x²+2xy+y²)-2xy(x+y)=(x²-y²)²+6xy(x+y)²
常数项就是不带有字母的项,所以这个式子中常数项是-5
∵|x+y+1|≥0,|xy-3|≥0|x+y+1|+|xy-3|=0,∴x+y+1=0,即x+y=-1xy=3xy3+x3y=xy(x²+y²)=yx[(x+y)²-2
应该是X3y-2x2y2+xy3原式=x3y-2x2y2+xy3=xy(x2-2xy+y2)=xy(x-y)2=17/36*6=17麻烦采纳,谢谢!
x+y=4,xy=2后者平方后二式相加再加后者平方
(x-y)2=x2-2xy+y2=9,当x2+y2=13时,13-2xy=9,解得xy=2.当xy=2,x2+y2=13时,x3y-8x2y2+xy3=xy(x2-8xy+y2)=2×(13-8×2)
∵x+y=3,∴(x+y)2=9,即x2+y2+2xy=9①,又x2+y2-3xy=4②,①-②,得5xy=5,xy=1.∴x2+y2=4+3xy=7.∴x3y+xy3=xy(x2+y2)=7.故答案
∵x-y=l,xy=2,∴x3y-2x2y2+xy3=xy(x2-2xy+y2)=xy(x-y)2=2×1=2.
x4-xy3-x3y-3x2y+3xy2+y4=(x4-xy3)+(y4-x3y)+(3xy2-3x2y)=x(x3-y3)+y(y3-x3)+3xy(y-x)=(x3-y3)(x-y)-3xy(x-
a1=a2,b1=-b2,c1=c2a1=a2,b1=b2,c1不等于c2a1不等于a2,b1不等于b2,c1不等于c2
顺便说一下,我算的算式是x^4-(2*x)*(2*x)*(2*x)+2^x=4共4个根,都是一样复杂,我给你贴了其中一个.
2x+3y=-k+2,①3x-2y=5k+3②2*①+3*②13x=13k+13所以x=k+1代入①y=-kx-y=2k+1=5k=2