搜搜考试网3m (m-1)
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原式=9-m2+m2-6m-7=-6m+2=-6*1/2+2=-1
m²+2m+1=0利用完全平方和公式：（m+1)²+0两边同时除以（m+1）m+1=0m=1将m=1带入m³+2m²+3m得：1³+2*1²
(m+1/m)=(m-1/m)+4=3*3+4=13m-1/m=（m-1/m）(m+1/m)=3√13
m*m-3m+1=0移项得m*m=3m-1可得m=3-1/m∴m+1/m=3两边平方,得m*m+1/m*m=9∵2m*m+2\m*m=2(m*m+1/m*m)代入,得2m*m+2\m*m=2×9=18
∵m>4∴m-4>0,7-2m0,m+1>0,m-3>0∴(m+1)(m-3)>0∴原式=|m-4|+|7-2m|+|(m-1)²|-|(m+1)(m-3)|=m-4+2m-7+(m-1)&
2m+6/m²-4m+4·1/m+3·（m-2)(m+3)/m+3=2（m+3）/（m-2）·1/m+3·（m-2)=2如追加其它问题,采纳本题后点击想我求助,
m平方-3m≠0m(m-3)≠0m≠0或m≠3如还有新的问题,请不要追问的形式发送,另外发问题并向我求助或在追问处发送问题链接地址,
2m(3m-5)+3m(1-2m)=146m^2-10m+3m-6m^2=14-7m=14m=-2
(m-1)+2(m²-3m)-(2-m+5m²)=m-1+2m²-6m-2+m-5m²=-3m²-4m-3
(m-3)/(m平方-1)÷(m平方-3m)/(m平方+2m+1)-1/(m-1)=(m-3)/(m-1)(m+1)×(m+1)²/m(m-3)-1/(m-1)=(m+1)/m(m-1)-m
括号里面乘出来：M-M^3+M^3-2M+2012>=0,M-2M+2012>=0,得：M
原式=3(m^2-2m+1)+(m^3+8)-(m^3+3m^2-3m)=3m^2-6m+3+m^3+8-m^3-3m^2+3m=11-3m
m>1且m>-15推出原式=m+2-(m-1)+m=m+3
3-2m>3m²-m+13m²-m+2m+1-3
(1m+3m+5m+...+2009m)-(2m+4m+6m+...+2008m)=1m+3m+5m+...+2009m-2m-4m-6m-...-2008m=1m+(3m-2m)+(5m-4m)+.
4.5*5=4.5+(4.5+1)+(4.5+2)+(4.5+3)+(4.5+4)+4.5+5)=4.5x6+1+2+3+4+5=27+15=42m*8=37.8m*n=m+(m+1)+(m+2)+(
m^2(m+3)+2m(m^2-1)-(m^4+m^3-m^2)/1/3m=m^3+3m^2+2m^3-2m-3(m^3+m^2-m)=3m^3+3m^2-2m-3m^3-3m^2+3m=mm=201
(m-1)/(m^2+3m+2)-6/(m^2-m-2)=(m-1)/(m+1)(m+2)-6/(m+1)(m-2)=(m-1)(m-2)/(m+1)(m+2)(m-2)-6(m+2)/(m+1)(m