3x除以(x-3)的平方-x除以(3-x)等于多少

(8x+9)/(x^2+x-6)=a/(x+3)+b/(x-2)8x+9=a(x-2)+b(x+3)8x+9=(a+b)x+(3b-2a)建立方程组a+b=83b-2a=9得到解a=3b=5

(1-x)^2/(x^2+4x+4)/(x-1)^2*(x^2+3x+2)/(x-1)=(x+1)/(x+2)(x-1)=(x+1)/(x^2+x-2)再问：是1-x的平方，不是（1-x）的平方再答：

x的平方-9分之x的平方-4x+4除以x的平方+3x分之x的平方-4除以x的平方=（x-2）²/(x+3)(x-3)÷（x+2）(x-2)/x(x+3)÷x²=（x-2）（x+2）

x≠-3,-1,1,5

格式有点乱,〖((1-x)/(3-x))^2/((x^2-6x+9)/(9-x^2 ))〗^ ×1/(x^2-2x+1)=〖((1-x)/(3-x))^2/(〖(X-3)〗^2/(

左边=6x/(x^2-9)=6x/[(x+3)(x-3)]右边=A/(x+3)+B/(x-3)=[A(x-3)+B(x+3)]/[(x+3)(x-3)]=[(A+B)x-3(A-B)]/[(x+3)(

1除以(x的平方+3x+2)+1除以(x平方+5x+6)+1除以(x平方+7x+12)=1/（x+1）（x+2）+1/(x+2)(x+3)+1/(x+3)(x+4)=1/(x+1)-1/(x+2)+1

=(x+2)(x-1)/(x-3)×(x-3)²/(x+2)=(x-1)(x-3)=x²-4x+3

1/(x+3)-6/(x^2-9)-(x-1)/(6-2x)=(x-3)/[(x-3)(x+3)]-6/[(x-3)(x+3)]+(x-1)/[2(x-3)]=[2(x-3)-12+(x-1)(x+3

原式=[3x/(x-1)-x/(x-1)]/[x/(x^2-1)]=[2x/(x-1)]/[x/(x+1)(x-1)]=2x+2解不等式组：x-6(x-2)≥2.(1)4x-2

4-4x+x^2分之2x-6除以（x+3)乘以3-x分之x^2+x-6=2(x-3)/(x-2)×1/(x+3)×(x+3)(x-2)/(3-x)=-2/(x-2)

先说答案x1=2x2=1/22(x*2+1/x*2)-3(x+1/x)-1=02(x+1/x)*2-4-3(x+1/x)-1=0(x+1/x)*2-3/2(x+1/x)-5/2=0(x+1/x-3/4

第n个数据=x的(n+1)次方除以[(2n-1)(2n+1)]

[(x的2次方+6x+9)除(x+3)](x的平方-3x+9)=（x+3）²÷（x+3）×(x²-3x+9)=(x+3)(x²-3x+9)=x³+27;很高兴为

x再答：第二个你错了再答：7x²再问：那x的3次方除以x的3次方等于多少呢？再答：1

将3x/(x-1)-x/(x+1)通分得

(x-x-4\x-3)除(x的平方-4\x-3)=[x(x-3)-(x-4)]／﹙x-3﹚÷﹙x+2﹚﹙x-2﹚／﹙x-3﹚=﹙x²-4x+4﹚／﹙x-3﹚*﹙x-3﹚／﹙x+2﹚﹙x-2﹚

y=(3x²+2x+2)/(x²+x+1)yx²+yx+y=3x²+2x+2(y-3)x²+(y-2)x+(y-2)=0x是实数,所以判别式大于等于0

【分析】(x-3)^2=(3-x)^2只需要提取公因式x/(3-x)3x/（x-3）^2-x/(3-x)=3x/（3-x）^2-x/(3-x)=x/(3-x)[3/(3-x)-1]=x/(3-x)*x

x^2-x+1>0所以3x=x^2-x+1x^2-4x+1=0x=2+根号3或2-根号3x^2+x+1=5x所以原式=x/5=(2+根号3)/5或(2-根号3)/5