3yx分之-7x
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依相反数的意义有|x-y+3|=-|x+y-1999|.因为任何一个实数的绝对值是非负数,所以必有|x-y+3|=0且|x+y-1999|=0.即x−y+3=0①x+y−1999=0②,由①有x-y=
∵x+y=4,xy=3,∴原式=x2+y2xy=(x+y)2−2xyxy=16−63=103.
∵3x-5y=0,∴x=5y3,∴原式=5y3−2y5y3+3y=-111.
7x的立方y的平方,8x的立方y,2分之1x的平方y的平方,-3yx的平方z,9x的4次方zy,zy的平方,-5分之1xyz,9y的立方z,0.3z的立方一共是九项,因为9y的立方z不含x,所以所有含
∵x−yx+y=2,∴x-y=2(x+y),∴x−yx+y-2x+2yx−y=2(x+y)x+y-2(x+y)2(x+y)=2-1=1,故答案为:1.
2x+yx2-2xy+y2•(x-y)=2x+y(x-y)2•(x-y)(2分)=2x+yx-y;(4分)当x-3y=0时,x=3y;(6分)原式=6y+y3y-y=7y2y=72.(8分)
4xy加5x²y加yx²再问:谢谢了,
x=6-3y &nbs
以x为主元,将方程整理为3x2-(3y+7)x+(3y2-7y)=0,∵x是整数,∴△=[-(3y+7)]2-4×3(3y2-7y)≥0,∴21−1439≤y≤21+1439,∴整数y=0,1,2,3
满足约束条件的平面区域如下图所示:联立x=yx+2y=3可得x=1y=1.即A(1,1)由图可知:当过点A(1,1)时,2x-y取最大值1.故答案为:1
=xy-3xy+2xy-xy=-xy
(1)x=4代入,4+y=4y-2y;所以y=4(2)y=4代入,4+4=4x-2*4;所以x=4
-x^2y+4x^2y-3yx^2-7x^2y^2+|-8x^2y^2|=-x²y+4x²y-3x²y-7x²y²+8x²y²=(
原式=7x²y+2yx²-2xy²+y²x-3xy²=9x²y-4xy²3x²y-5xy²=-2x²
∵|x-y+3|+|x+y-1999|=0,∴x-y+3=0,x+y-1999=0,即x-y=-3,x+y=1999,则x+yx−y=1999−3=-19993.
由题意得,x−y=2x−2y+3=3,解得:x=4y=2,则可得a=3,b=2,b-a=-1,-1的立方根为:-1.
6x^2y+2xy-3x^2y^2-7x-5yx-4y^2x^2-6x^2y=6x^2y-6x^2y+2xy-5yx-3x^2y^2-4y^2x^2-7x=-3xy-7x^2y^2-7x
6x²y+2xy-3x²y²-7x-5yx-4y²x²-6x²y|x+3|+(y+1/2)²=0x=-3y=1/2=-3xy-7x
y=98z=99x=9803由题意得一下三个式子:x=100y+3一x=99z+2二x