4x-5与2x-1除以二值相等,x等于-搜答案-搜搜考试网

列出等式.三分之2x+4＝六分之5x-1两边同时乘以6.约分后得2(2x+4)=5x-1化简得4x+8=5x-14x-5x=-1-8-x=-9x=9当X=9时.两式相等

2x＾2+7x-1=4x-12x^2+7x-1-4x+1=02x^2+3x=0x(2x+3)=0x=0或-3/2当x为0或-3/2时,代数式2x＾2+7x-1与4x-1的值相等

2x^2+7x-1=4x+12x^2+3x-2=0(2x-1)(x+2)=0x=1/2或x=-2

((x+2)/(x^2-2x)-(x-1)/(x^2-4x+4))/((x^2-16)/(x^2+4x))=((x+2)(x-2)-(x-1)x)/((x-2)^2*x)/((x-4)/x)=((x-

3再问：要过程再答：x^2-4x+5=x^2-3x+23=x

x/(x²-x+1)=7x²-x+1=x/7x²+1=8x/7平方x^4+2x²+1=64x²/49两边减去x²x^4+x²+1=

(5x-2)/(x-1)+1=(4x+5)/(3x-3)(5x-2+x-1)/x-1=(4x+5)/(x-1)*36x-3=(4x+5)/314x=14x=1

2(3x-5)=6-(1-x)6x-10=5+x6x-x=5+105x=15x=3

5x+1/2-3x=7x-7/315x+3-18x=14x-14-3x-14x=-14-3-17x=-17∴x=1

三分之四(1-2x)=七分之二(3x+1)28(1-2x)=6(3x+1)28-56x=18x+674x=22x=11/37当x=11/37时,代数式三分之四(1-2x)与代数式七分之二(3x+1)的

4x/(2x-1)-(x+1)/(x-2)=1先通分[4x(x-2)-(x+1)(2x-1)]/[(2x-1)(x-2)]=14x2-8x-(2x2+x-1)=2x2-5x+2x=-1/4其中x2代表

x等于-8分之31再问：步骤。再答：2（2x-5)=3(4x+7)4x-10=12x+21-8x=31得x=-31/8

5x+4+2x=4x-3，移项得5x+2x-4x=-3-4，合并得3x=-7，系数化为1得x=-73，所以x=-73时，5x+4+2x与4x-3的值相等．

4x/2x-1=2x+1/x-2方程两边都乘以（2x-1)(x-2)4x(x-2)=(2x+1)(2x-1)4x^2-8x=4x^2-1-8x=-1x=1/8经检验：x=1/8是方程的解.

由题意得：4（2x+1）=5x+38x+4=5x+38x-5x=3-43x=-1x=-1/3∴当x=-1/3时,代数式4（2x+1）与5x+3的值相等【中学生数理化】团队wdxf4444为您解答!

1/(5-x)+2/(4-x)+3/(3-x)=-31/(5-x)+2/(4-x)=3/(x-3)-3[(4-x)+2(5-x)]/[(5-x)(4-x)]=[3-3(x-3)]/(x-3)(14-3

5x(x+a)-2(2x^2-x-1)=x^2+4x+25x^2+5ax-4x^2+2x+2=x^2+4x+2x^2+(5a+2)x+2=x^2+4x+25a+2=4a=2/5

这是一元一次方程求解的问题,是比较简单的①4(x-1)+2-x=2(4-x)-64X-4+2-X=8-2X-63X-2=2-2X5X=4X=4/5②将x=-3代入方程,原式为K(-3+4)-2K-（-

5x-2=2x+43x=6x=2

4x/2x-1=2x-1/x-2（2x-1）*（2x-1）=4x*（x-2）x=-1/4