5x²-6xy 2y² 2x-2y 3
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![5x²-6xy 2y² 2x-2y 3](/uploads/image/f/352524-12-4.jpg?t=5x%C2%B2-6xy+2y%C2%B2+2x-2y+3)
5x平方+8xy-4y平方
设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y
-6x²y-x+5x²y-2x+x³y+3x=-6x²y+5x²y-x-2x+3x+x³y=-x²y+x³y
设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2
3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)
2(2x+3y)(3x+2y)-(6x-y)(2x-5y)=12x^2+26xy+12y^2-(12x^2-32xy+5y^2)=12x^2+26xy+12y^2-12x^2+32xy-5y^2=58
方程两边同时进行通分可得[5(x2-16)+96]/(x2-16)=[(2x-1)(x-4)+(3x-1)(x+4)]/(x2-16)再问:不好意思这是两道题再答:这好似第一个原式=(x+y)[(x-
(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x
1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)(2a+b)(2
(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)=x-2x-3x-4x-..-10x+y*(1-1/2-1/6-1/12-..1/90
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
(x+y)ˆ2-2(x+y)(x-y)+(x-y)ˆ2=(x+y-x+y)^2=(2y)^4=4y^2如果满意请点击右上角评价点【满意】即可~再问:这个我看不懂,能不能写下来啊,谢
(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-(x-y)^(5+3+2)=-(x-y)^10
解题思路:本题目应该是9y的平方吧,要不然没法做出来。解题过程:(2x-6y)/(x的平方-9y)=2(x-3y)/[(x-3y)(x+3y)]=2/(x+3y)=2/3
(x+2y)(x-2y)-(x-4y)(x+4y)+(6y-5x)(6x-5y)=x^2-4y^2-x^2+16y^2+36xy-30y^2-30x^2+25xy=-18y^2+61xy-30x^2
x(x*x-1)+x(5-x*x)-6y+7=-x+5x-6y+7=2(2x-3y)+7=2*(-4)+7=-8+7=-1再问:能在写详一点吗-x+5x-6y+7再答:x(x*x-1)+x(5-x*x
(2X-3y)-(5x-y)=2x-3y-5x+y=2x-5x-3y+y=(2x-5x)+(-3y+y)=-3x-2y这样写总是全过程了吧
(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.-(10x+1/90y)=x+y-2x-1/2y--3x-1/6y-4x-1/12y-5x-1/20y
平方和绝对值都大于等于0,相加等于0若有一个大于0,则另一个小于0,不成立.所以两个都等于0所以x+1=0,y-1/2=0x=-1,y=1/2原式=4x^2-y^2+3(4x^2-4xy+y^2)-9