9x^3 6x^2y-3xy^2
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:(2x-y)(x^2+xy-2y^2)=(2x-y)(x+2y)(x-y)xy(x^2-xy)(-3xy^2)=xy*x(x-y)*(-3xy^2)=-3x^3y^3(x-y)
原式=x²-y²-(4x²y²+12xy²+9y²)=x²-y²-4x²y²-12xy²-
3xy是3x原式=(x-3y)(x+2y)+3x+y+2十字相乘x-3y2×x+2y1所以原式=(x-3y+2)(x+2y+1)
对.前提是x不等于y
3xy[2xy-x(y-2)+x-1]=3xy(2xy-xy+2x+x-1)=3xy(xy+3x-1)=3x^2y^2+9x^2y-3xy
3xy[2xy-x(y-2)+x]=3xy[2xy-xy+2x+x]=3xy(xy+3x)=3x²y²+9x²y
(3xy)平方/(-xy)+(x-2y)平方-(x+2y)(x-2y)=-9xy+(x-2y)(x-2y-x-2y)=-9xy+(x-2y)(-4y)=-9xy-4xy+8y²=8y
Solution:x^2-2xy+3y^2=9(1)4x^2-5xy+6y^2=30(2)Eq(1)*5-Eq(2)*2,wehavex^2-y^2=5(3)Eq(2)-Eq(1),wegetx^2+
(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^
【x²+xy/(x-y)】/【xy/(x-y)】=【x²(x-y)/(x-y)+xy/(x-y)】/【xy/(x-y)】={【x²(x-y)+xy】/(x-y)}/【xy
1、已知2x²+xy=10,3y²+2xy=6,求4x²+8xy+9y²的值为?分析:通过观察,可以把8xy拆成2xy+6xy,分别于剩余的两项组合,并提取公因
方是什么是平方吗再问:嗯再答:=x(2x-3)-3y(2x-3)=(2x-3)(x-3y)
x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2=16x^3y^3-49x^3y^3-45^3y^3=-78x^3y^3如果本题有什么不明白可以追问,
7或者-8再问:求过程^_^再答:两个等式两边相加
首先我们得知道(a+b+c)^2=a^2+b^2+c^2+ab+bc+ca然而题目中刚好有x^2+y^2+2xy-3x-3y+9,是(a+b+c)^2的形式即(x+y-3)^2所以:(x+y+3)(x
[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/
[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)=[x²y(xy-1)-yx&sup
1、(-7x^y)(2x^y-3xy^3+xy)=-14x^(2y)+21x^(y+1)y^3-7x^(y+1)y;2、((x-y)^6)/((y-x)^3)/(x-y)=-(x-y)^3/(x-y)
原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&
2x-3√(xy)-2y=0(2√x+√y)(√x-2√y)=0因为x>0,xy≥0所以y≥02√x+√y>0所以√x-2√y=0,即x=4y(x^2+4xy-16y^2)/(x^2+xy-9y^2)