已知2x加5y减3等于0,求9的x幂乘27的y次幂的值
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![已知2x加5y减3等于0,求9的x幂乘27的y次幂的值](/uploads/image/f/4205272-40-2.jpg?t=%E5%B7%B2%E7%9F%A52x%E5%8A%A05y%E5%87%8F3%E7%AD%89%E4%BA%8E0%2C%E6%B1%829%E7%9A%84x%E5%B9%82%E4%B9%9827%E7%9A%84y%E6%AC%A1%E5%B9%82%E7%9A%84%E5%80%BC)
x的平方-4x+y的平方+2y+5=x的平方-4x+4+y的平方+2y+1=(x-2)^2+(y+1)^2=0x-2=0x=2y+1=0y=-1x+y=2-1=1
X+Y=5,XY=2,5X+4Y-3X-2Y+XY=2X+2Y+XY=2(X+Y)+XY=2×5+2=12.
因为……(原式)所以x^2-9=0,y+3=0所以x=3或-3,y=-3所以x+y=0或-6
已知x方加y方减2x加4y等于-5x方+y方-2x+4y+5=0x方-2x+1+y方+4y+4=0(x-1)方+(y+2)方=0所以x-1=0,y+2=0所以x=1,y=-2如果不懂,请追问,祝学习愉
∵(x+1)²+|y-2|=0 ∴x+1=0 y-2=0 ∴x=-1 y=2 ∴x²y²+3xy-7x²y²-(5/2)xy+1+5x²
4x²+9y²+12y-4x=5这个不对,应该等于-5把5拆成1+4(4x²-4x+1)+(9y²+12y+4)=0(2x-1)²+(3y+2)&su
x^2+y^2-4x+2y+5=0,配方得(x-2)^2+(y+1)^2=0,所以x=2,y=-1,因此(x+3y)^2008=(2-3)^2008=(-1)^2008=1.
已知x加2的平方加3减y绝对值等于0,求xy减x减y的值(x+2)^2+/3-y/=0,(x+2)^2>=0,/3-y/>=0所以(x+2)=0x=-23-y=0y=3xy-x-y=-6+2-3=-7
根据题意知:X/3=Y/4=Z/5设X/3=Y/4=Z/5=K则X=3K,Y=4K,Z=5K所以(X+Y)/(X-2Y+3Z)=(3K+4K)/(3K-2*4K+3*5K)=7K/(10K)=7/10
xy分之x加y等于2∴x+y=2xy3x减5xy加3y分之负x加3xy减y=[-(x+y)+3xy]/[3(x+y)-5xy]=(-2xy+3xy)/(6xy-5xy)=xy/(xy)=1
x^2+y^2+2x-4y+5=0,(x+1)^2+(y-2)^2=0,x=-1,y=2(-1)^2006-1/2=1-1/2=1/2
原等式可化为:x²-2xy+y²+6(x-y)+9+y²=0即:(x-y)²+6(x-y)+9+y²=0(x-y+3)²+y²=0
稍等一下再答:解已知|3x+2y+3|+(5y+2x-9)²=0∴3x+2y+3=0(1)5y+2x-9=0(2)(1)×2得:6x+4y+6=0(3)(2)×3得:15y+6x-27=0(
x^2+3y^2-12y+12=0x^2+3(y-2)^2=0所以x^2=0,3(y-2)^2=0x=0,y-2=0y=2y^x=2^0=1
2x-y=3mx+2y=4m+5(1)+(2)×35x+5y=3m+12m+15=15m+15x+y=3m+3因为x+y=0所以3m+3=0m=-1
x²+y²-4x-2y+5=0x²-4x+4+y²-2y+1=0(x-2)²+(y-1)²=0x-2=0x=2y-1=0y=1√(x+y)/
3x-6y-5=03(x-2y)=5x-2y=5/32x-4y+6=2(x-2y)+6=2×5/3+6=28/3或9又1/3
已知xy/(x+y)=2,求:(3x-5xy+3y)/(-x+3xy-y)xy/(x+y)=2得:xy=2(x+y)(3x-5xy+3y)/(-x+3xy-y)=(3x-9xy+3y+4xy)/(-x