已知y=sin^2 3x,求dy
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![已知y=sin^2 3x,求dy](/uploads/image/f/4231179-27-9.jpg?t=%E5%B7%B2%E7%9F%A5y%3Dsin%5E2+3x%2C%E6%B1%82dy)
sin(x^2+y^2)=x两边同时求导,得(x^2+y^2)'cos(x^2+y^2)=dx(2xdx+2ydy)cos(x^2+y^2)=dx2xdx+2ydy=dx/cos(x^2+y^2)2y
y'=2xsin4x-x²cos4x·4所以dy=(2xsin4x-4x²cos4x)dxy=ln√4+t²=1/2ln(4+t²)y'=1/2·1/(4+t&
∵dy/dx=sin(x-y)==>dy=sin(x-y)dx==>dx-dy=dx-sin(x-y)dx==>d(x-y)=(1-sin(x-y))dx==>d(x-y)/(1-sin(x-y))=
dy/dx=1+du/dx*x+u*dx/dx+cosv*dv/dx=1+x*e^x+e^x+cos(lnx)*(1/x)
Y=secX+a的2X次方+sin派/3,求dyy=secx+a^(2x)+sinpai/3dy/dx=tanxsecx+a^(2x)*lna*(2x)'dy=(tanxsecx+2a^(2x)*ln
cos(x+y)(1+y')=y+xy'dy/dx=y'=[y-cos(x+y)]/[cos(x+y)-x]
x=sin(y/x)+e^2求dy/dxd(x)=d(sin(y/x)+e^2)dx=dsin(y/x)+de^2dx=cos(y/x)d(y/x)dx=cos(y/x)(xdy-ydx)/x^2x^
dy=dsinlnx+d(1/x)=cos(lnx)dlnx+(-1/x²)dx=cos(lnx)*1/xdx-1/x²dx=[xcos(lnx)-1]/x²dx
y=sin(e∧x+1)dy=cos(e^x+1)d(e^x+1)=e^xcos(e^x+1)dx
加油啊,不然大学考不起啊!
y=x*sin(lnx)y'=sin(lnx)+x*cos(lnx)*(lnx)'=sin(lnx)+x*cos(lnx)*1/x=sin(lnx)+cos(lnx)dy=[sin(lnx)+cos(
dy=2sin[x(x+1)]cos[x(x+1)](2x+1)
y=(lnx)^3+(sinx)^2y'=dy/dx=3(lnx)^2/x+2sinxcosx=3(lnx)^2/x+sin2xdy=[3(lnx)^2/x+sin2x]dx
y=sin(x+y)dy=cos(x+y)(dx+dy)dy=cos(x+y)dx+cos(x+y)dydy/dx=cos(x+y)/(1-cos(x+y))
1=x?
e是自然对数底,约等于2.71828,是sine是常数,其导数是0,故dy=(x/Lnx)'*dx=dx*(lnx-1)/ln^2x注意:求导数和微分是有区别的.
dy=cos(2x+e^2x)*(2+2e^2x)dx
第二步确实应该是d(tanx²)=sec²x²d(x²)
dy/d(x^3)=(dy/dx)/(d(x^3)/dx)=cosx/3(x^2)
已知,lny=(sinx)*e^y.求dy/dx解一:利用隐函数求导公式求解【建议你用这个】设F(x,y)=lny-(sinx)e^y=0则dy/dx=-(∂F/∂x)/(