cot^2x-1

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cot^2x-1
lim(cosx)^cot^2x当x趋近于0

原式=lim(x->0)e^[cot²xln(cosx)]=e^[lim(x->0)ln(cosx)/tan²x]=e^[lim(x->0)ln(cosx)/x²]=e^

求极限LIM(趋近与0)(cot^2 *x-1/x^2)

LIM(趋近与0)(cot^2x-1/x^2)=lim(x^2*cos^2x-sin^2x)/(x^2*sin^2x)=lim[(x^2+1)cos^2x-1]/x^4=lim[(1/2)*(x^2+

已知cot(x/2)=t 则cosx/(1-sinx)可用t表示介绍

cosx/(1-sinx)=[(cosx/2)^2-(sinx/2)^2]/(cosx/2-sinx/2)^2=(cosx/2+sinx/2)/(cosx/2-sinx/2)=(cotx/2+1)/(

如题,求证:sin2x/ [(sinx+cosx-1)(sinx+1-cosx)] =cot(x/2)

sin2x/[(sinx+cosx-1)(sinx+1-cosx)]=sin2x/[(sinx-(1-cosx)(sinx+1-cosx)]=sin2x/[(sin^2x-(1-cosx)^2]=si

求证!(1 + cosx )/sinx = cot(x/2)

1+cosx=1+2(cosx/2)^2-1=2(cosx/2)^21+cosx-------=2(cosx/2)^2/2sin(x/2)*cos(x/2)=cot(x/2)sinx

tan x /(1-cot x) + cot x /(1-tanx) = 1+ sec x csc x

tanx/(1-cotx)+cotx/(1-tanx)=tanx/(1-cosx/sinx)+cotx/(1-sinx/cosx)=sinxtanx/(sinx-cosx)+cosxcotx/(cos

1、1+cosx/1-cosx + 1-cosx/1+cosx=4cot^2x+2

(1+cosx)/(1-cosx)+(1-cosx)/(1+cosx)通分=((1+cosx)^2+(1-cosx)^2)/1-cos^2(x)=2*(1+cos^2(x))/sin^2(x)因为1=

求下列不定积分:1、(cot)^2•xdx 2、cos2x/(cos^2xsin^2x)dx

1、∫(cot)^2•xdx=∫[(csc)^2•x-1]dx=-cotx-x+c2、∫cos2x/(cos^2xsin^2x)dx=∫(cos^2x-sin^2x)/(cos

x →0时lim(1+x^2)^cot^2x求极限要详细过程.

lim(1+x²)^cot²x=lim(1+x²)^(1/x²)(x²cot²x)=lime^(x²/tan²x)=e

用洛必达法则求limx→0(1/x^2-cot^2x)的详细步骤

limx→0(1/x^2-cot^2x)=limx→0(1/x^2-sin^2x/cos^2x)=limx→0[(sin^2x-x^2cos^2x)/x^2sin^2x]=limx→0[(sin^2x

x趋向1负时,求lim【ln(1-x)+tan派/2*x】/cot派*x,谢谢

/>lim[ln(1-x)+tanπx/2]/cotπx=limln(1-x)/cotπx+limtanπx/2/cotπx=limsin²πx/[π(1-x)]+lim2tan²

lim(x→0)=(1/x^2-cot^2x)

lim(x→0)=(1/x^2-cot^2x)=lim(x→0)=(1/x^2-1/tan²x)=lim(x->0)(tan²x-x²)/x²tan²

怎么证明tan^2x+cot^2x=2(3+cos4x)/1-cos4x

tan^2x+cot^2x=tan^2x+1/tan^2x=[(sinx)^4+(cosx)^4]/(sinxcosx)^2={[(sinx)^2+(cosx)^2]^2-2(sinxcosx)^2}

lim (arcsinx/x)^{[cot(x)]^2} x→0

我算了下,你看看行不lim(arcsinx/x)^{[cot(x)]^2}(x→0)=lim[1+(arcsinx-x)/x]^{[cot(x)]^2}(x→0)=lim[1+(arcsinx-x)/

用等价代换limx趋于0(1/x^2-cot ^2x)

当枯叶化作灰烬的尘埃我们在餐桌上生下孩子,又在餐桌上准备父母的葬礼.我一小块花园.人面多麽佳丽无奈船已远航为了那气息——它仍在那里摇荡.面的么打击,他们为能无力改变哈哈

y=-1/2cot(π/3-2x)的周期为?单调区间为?

y=-1/2cot(π/3-2x)=1/2cot(2x-π/3)周期T=π/2单调区间kπ=

x趋向于0 lim(1+tanx)^1-2cot 求极限

x趋近于0时,tanx→x,cotx→1/x,(1+x)^(1/x)→e原式=lim(1+x)^(1-2/x)=lim(1+x)/(1+x)^(2/x)=1/e²

求不定积分 (tanx+2cot^2x)^2dx

原式=∫[(tanx)^2+4cotx+4(cotx)^4]dx=∫[(secx)^2-1]dx+4∫cotxdx+4∫[(cscx)^2-1]^2dx=tanx-x+4∫d(sinx)/sinx+4