C语言 输入一个整数,判断它能否被3,5,7整除
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![C语言 输入一个整数,判断它能否被3,5,7整除](/uploads/image/f/528522-42-2.jpg?t=C%E8%AF%AD%E8%A8%80+%E8%BE%93%E5%85%A5%E4%B8%80%E4%B8%AA%E6%95%B4%E6%95%B0%2C%E5%88%A4%E6%96%AD%E5%AE%83%E8%83%BD%E5%90%A6%E8%A2%AB3%2C5%2C7%E6%95%B4%E9%99%A4)
#includevoidmain(){intN,status=0;printf("输入这个数:");scanf("%d",&N);if(N%3==0)status++;if(N%5==0)status
#includeintmain(){intn;scanf("%d",&n);if(n>0){if(n%2)printf("此数为正数且为奇数.");elseprintf("此数为正数且为偶数");}e
#includeintmain(intargc,char*argv[]){intnum;printf("输入一整数:");scanf("%d",&num);if(num%3==0&&num%5==0&
if(a%2==0);有个分号
方法很多啊,比如判断每一位是否是数字,再比如先把字符串atol转换成数字,再转换成字符串,看是否相等.再问:第一条再答:既然限制了用空格分开,一个回车输入10个数,只能先把变量或数组都赋值成0,用sc
我把SCANF里的中文去掉就正常了.
a+b>cabs(a-b)再问:能编个完整的给我吗?谢谢。新手,看不懂啊……不胜感激再答:#includeinta,b,c;scanf("%d,%d,%d",&a,&b,&c);if(a>0&&b>0
方法一://用数学函数#include#includevoidmain(){inta;scanf("%d",&a);printf("%d\n",abs(a));}方法二://判断#includevoi
//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){\x05intn,sum=0;printf("Typeaninte
#includeintmain(){intnum;inta;//百位intb;//十位intc;//个位scanf("%d",&num);a=num/100;//默认强制转为整型b=(int)(num
#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%5==0)c=1;if(a%7==0)d=1;elseif(c==1&&d==1)p
#include"stdio.h"#include"iostream"intmain(){inti,x,y=1;scanf("%d",&x);for(i=2;i
以下是关键代码intnum;//这个是要你判断的数if(num%3==0&&num%5==0)//判断能否被整除printf("能被3和5整除");
#includevoidmain(){\x09longa;\x09printf("inputanumber:\n");\x09scanf("%d",&a);\x09if(a%3==0&&a%5==0&
voidmain(){intn;printf("请输入一个整数:");scanf("%d",&n);if(n%3==0&&n%5==0&&n%7==0)printf("\n此数能被3,5,7整除\n"
各位数相加和能被3整除,那么这个数就能被3整除,如258各位数相加等于15,15能被3整除,那么258也能被3整除.能够被5整除的只要各位数是0或5就行啦.15和10都能被5整除.另外,0除以任何数都
inta,b;scanf("%d%d",&a,&b);while(a{intt=a;a=b;b=t;}if(a%b==0)printf("a能被b整除");elsepr
#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin
#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%3==0)b=1;if(a%5==0)c=1;if(a%7==0)d=1;if(b*
#include#includevoidmain(){\x09intn,i;\x09scanf("%d",&n);\x09if(n==1)\x09{\x09\x09printf("1isnothing