C语言输入一个不超过四位的正整数,要求输出位数及每位数上相应的数字

voidmain(){intn=-1;while(n

//z2.cpp:定义控制台应用程序的入口点.//#include"stdafx.h"#include#includeusingnamespacestd;voidReverse(int&m)//m为4

这设计到计算机的数值表示问题,一般32位的计算机用unsignedlonglong最大能表示的也只到18446744073709551615,所以超过20位做运算时就因为计算机不能表示而出错了.对于这

main(){longinta;intb,c,d,e,f;scanf("%ld",&a);while(a>=1&&a=1&&a/10000=1&&a/1000=1&&a/100=1&&a/10=1&&

#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);

#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}

inti=2123;intone,two,three,four;one=i%10;//各位two=(i/10)%10;//十位three=(i/100)%10;//百位four=(i/1000)%10

#include#defineN30typedefstructstudent{\x09charname[10];\x09intscore;}STU;voidmain(){\x09STUs[N];\x0

太简单了吧#includevoidmain(){intA,bai,shi,ge;printf("请输入一个三位整数A：");scanf("%d",&A);bai=A/100;shi=A%100/10;

#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol

intmain(intargc,char*argv[]){inti=0,j,tmp;intarr[4]={0};scanf("%d",&j);printf("yourinputwas:%d\n\n",

#include "stdio.h"int main(){  double x;  int y;&n

用一个数组依次保存每一位的值,然后输出就成了.如a=12345,tmp=a循环处理,直到tmp==0；tmp%10=5,将5保存tmp=a/10;将保存的内容输出就行了……

#includemain(){inta,b;scanf("%d",&a);for(;a>=1;){b=a%10;printf("%d",b);a/=10;}printf("\n");}

#include#includeintmain(void){\x09chara[20];\x09printf("请输入数字");\x09scanf("%s",a);\x09printf("%c",a[

#include"stdio.h"typedefstruct{intyear;intmonth;intday;}Date;boolIsLeapYear(intyear){if(year%4==0){i

#includeintmain(){inti,s,t,a[100]={0};t=0;s=0;for(i=0;i

#includevoidmain(){intnum;printf("Enteranumber!(9

#include#includeintmain(){intn;intt,l=0;inti,j;printf("输入n:");scanf("%d",&n);t=n;while(t){

#include#includevoidconv(char*s){inti;for(i=strlen(s)-1;i>=0;i--)putchar(s[i]);printf("\n");}in