求过两圆x² y² 4x y=-1 面积最小
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![求过两圆x² y² 4x y=-1 面积最小](/uploads/image/f/5749319-47-9.jpg?t=%E6%B1%82%E8%BF%87%E4%B8%A4%E5%9C%86x%C2%B2+y%C2%B2+4x+y%3D-1+%E9%9D%A2%E7%A7%AF%E6%9C%80%E5%B0%8F)
X²+Y²+X²Y²-4XY+1=0(X-Y)^2+(XY-1)^2=0所以X-Y=0XY-1=0(X-Y)^2008-(XY)^2008=0^2008-1^2
(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-6xy+3x-3y=-6×(-2)+3×1=15
5xy+4x+7y+6x-3xy-4xy+3y=5xy-3xy-4xy+4x+6x+7y+3y=(5-3-4)xy+(4+6)x+(7+3)y=-2xy+10x+10y=-2xy+10(x+y)因为x
原式=3x-3y-6xy=3-12=-9
1/x+1/y=5两边乘以xy得y+x=5xy∴x+y=5xy3x+4xy+3y/x+3xy+y=[3(x+y)+4xy]/[(x+y)+3xy]=(15xy+4xy)/(5xy+3xy)=19xy/
(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6xy+3*(x-y)当时,原式=-6*1+3*
由已知通分Y-X=4XY所以所求=-2(Y-X)+xy/-(Y-X)-2XY=-7XY/-6XY=7/6
∵1/x-1/y=4∴(y-x)/xy=4∴y-x=4xy∴x-y=-4xy(2x+xy-2y)/(x-2xy-y)=[2(x-y)+xy]/[(x-y)-2xy]=(-8xy+xy)/(-4xy-2
解题思路::∵x+y=0,x+13y=1,解得x=1/12,y=-1/12∴x²+12xy+13y²=1/144-1/12+13/144=14/144-1/12=2/144=1/72解题过程:已知x+
3-y=0x+y=0∴x=-3y=3[2(x+y)-3(xy+4)]÷1/xy=[2×0-3(-9+4)]÷(-1/9)=15×(-9)=-135
1/x-1/y通分=(y-x)/xy=3y-x=3xyx-y=-3xy所以原式=[3(x-y)+4xy]/[(x-y)-2xy]=[3(-3xy)+4xy]/[(-3xy)-2xy]=-5xy/(-5
(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=(-2xy-3xy-xy)+(2x+2x-x)+(3y-2y-4y)=-6xy+3x-3y=-6+3*3=3
根据根号和绝对值的非负性可知,只有1-3x=0且6y-5=0所以x=1/3,y=5/6xy=5/18
5x²+5xy+y²+2x+1=04x²+y²+4xy+2x+x²+1=0(2x+y)²+(x+1)²=0得{2x+y=0---①
得y-x=3xyx-y=-3xy原式=-15xy+2xy/-3xy-4xy=-13/-7=13/7
①xy同非负时,2x-3√xy-2y=(2√x+√y)(√x-2√y)=0∴√x=2√y,x=4y②xy同负时,2x-3√xy-2y=[2√(-x)+√(-y)][√(-x)-2√(-y)]=0∴√(
同除xy原式变形为:(3/y-4+3/x)/(1/x+2+1/y)=5/5=1
0=x^2+y^2+x^2y^2-4xy+1=x^2+y^2-2xy+x^2y^2-2xy+1=(x-y)^2+(xy-1)^2,两个平方数的和等于0,所以,x=y,xy=1,带入得(x-y)^200
(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6*(-2)+3*1=15不懂可追问,有帮助请采