用C语言编写一个调用函数能被3和5整除的数
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#includeusingnamespacestd;doublecentigrade(doubleF){doubleC=(F-32)*5.0/9;returnC;}intmain(){doubl
#include <stdio.h>float sum1(int n);float sum2(int n);void main(
#includeintfun(intn){ints=0;while(n){s+=n%10;n=n/10;}returns;}main(){intn;scanf("%d",&n);printf("%d\
#include<stdio.h>int f(int x ){\x09if ( x>0 )\x09\x09return&n
#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s
#include#defineN4floatmid(int*a){inti,j,t;floatmiddle;for(i=0;i
intjc(intx){returnx==1?1:jc(x-1)*x;}再问:可以编一个完整的么?我直接运行试一下。。。新手,不好意思,,,,谢谢再答:intjc(intx){returnx==1?1
上面是对的,f1是求体积的,f2是求表面积的.
#includedoubleH(intn,doublex){if(x>1){if(n==0)return1.0;//H0(x)=1;if(n==1)return2.0*x;//H1(x)=2x;//直
#include#includeintmax(inta,intb){if(a>b)returna;if(a
我刚刚看到你第一个函数求最大公约数的算法都错了我写了一个求12和14的最大公约数的你先看看在自己琢磨下还有没有其他问题.#includevoidmain(void){intt,max,a=12,b=1
测试可用.程序结果:15,45,51,54,57,75#includevoidmain(){intfunc(inti);intr;inti;for(i=10;i
#includevoidshow();voidmain(){show();}voidshow(){printf("Ilovechina!");}
#include<stdio.h>#define Pi 3.14159double Square(double r){ &nb
#includevoidsort(int*p,int*q,int*t){inttemp;if(*p>*q){temp=*p;*p=*q;*q=temp;}if(*p>*t){temp=*t;*t=*p
#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\
#include#defineN9voidmain(){inti,j,a[N][N]={0};for(i=1;i
#include<stdio.h>#include<math.h>#define pi 3.141526int main(){//假定单位圆半径为
#include<stdio.h>#include<math.h>void zero(float a,float b);void lef
//今天被百度吞了4份代码,上帝保佑这个别被吞了,哥的分数啊.#includeintmain(){intn,i,j;scanf("%d",&n);for(i=1;i