用因式分解解方程4(x-3)-25(x-2)=0
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![用因式分解解方程4(x-3)-25(x-2)=0](/uploads/image/f/6268702-22-2.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E8%A7%A3%E6%96%B9%E7%A8%8B4%28x-3%29-25%28x-2%29%3D0)
3x²+5x=0x(3x+5)=0∴x=0x=-5/3(2a-1)²=02a-1=0a=1/2(2x-5)²=92x-5=32x-5=-3x=4x=1(2x+x-1)(2
移项再化一下得(2x)²-(3x-2)²-0用平方差公式得(2x+3x-2)(2x-3x+2)=0x1=0.4,x2=2
(3x+2)^2=4(x-3)^2(3x+2)^2-4(x-3)^2=0(3x+2+2x-6)(3x+2-2x+6)=0(5x-4)(x+8)=0x=4/5或x=-8
解由(根号3+1)x^2=2x得(√3+1)x^2=2x即(√3+1)x^2-2x=0即x[(√3+1)x-2]=0即x=0或(√3+1)x-2=0即x=0或x=2/(√3+1)=2(√3-1)/(√
(4-x)(3x+6)=0-3(x-4)(x+2)=0x1=4,x2=-24y(y-1)=2y(y-1)4y(y-1)-2y(y-1)=02y(y-1)=0y1=0,y2=1
(x-2)(x-2)=4x-8(x-2)(x-2)=4(x-2)(x-2)((x-2)-4)=0(x-2)(x-6)=0所以:x-2=0即x=2或x-6=0即x=6即解为:x=2,x=6(3x-4)^
3x²‐2x=0x(3x-2)=0则x=0或3x-2=0,x=2/3应该是这样的吧
把(x-3)作为公因数提出来(x-3)*(x-3+4x)=0(x-3)*(5x-3)=0所以x1=3,x2=3/5=0.6
4x^2-25x+6=0(4x-1)(x-6)=0x1=1/4,x2=6
x^2+2x-4=0(x^2+2x+1)-5=0(x+1)^2-5=0(x+1+√5)(x+1-√5)=0x1=-1-√5x2=-1+√5
5x²-4x=0x﹙5x-4﹚=0x1=0x2=4/5.
移项4x²-1=0(2x+1)(2x-1)=0x=-1/2,x=1/2
(3x+2)平方=4(x一3)平方(3x+2)²-4(x一3)²=0[(3x-2)+2(x-3)][(3x-2)-2(x-3)]=0(3x-2+2x-6)(3x-2-2x+6)=0
(3x+1)(x-1)=(2x-5)(x-1)(3x+1)(x-1)-(2x-5)(x-1)=0(x-1)(3x+1-2x+5)=0(x-1)(x+6)=0x=1,x=-6
(5x-3)^2=(2x+1)^25x-3=2x+1或5x-3=-2x-13x=4或7x=2x=4/3或x=2/73(x+3)^2=x^2+x3x²+18x+27=x²+x2x
解题思路:先提取公因式x对等式的左边进行因式分解,即利用因式分解法解方解题过程:利用因式分解解方程:3x2-4x=0.解:由原方程,得x(3x-4)=0,∴x=0或3x-4=0,解得,x
(x-1)(2x+3)+x(1-x)=0(x-1)(2x+3)-x(x-1)=0(x-1)(2x+3-x)=0(x-1)(x+3)=0x-1=0x=1x+3=0x=-3
x(x²+4)=0x²+4>0,即不会等于0所以x=0
3x²-6x=-4x+83x²-2x-8=0(3x+4)(x-2)=0x=-4/3,2再问:第三步能详细点吗谢谢--再答:十字相乘法:3x41x-2————-6x+4x=-2x