limsin(x平方-9) x-3=
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x平方+6x-9=x²+6x+9-18=(x+3)²-18=(x+3-3√2)(x+3+3√2)
原式=(x-3)^2)*[(x+3)/(x-3)(x-6)]=(x+3)(x-3)/(x-6)=(x^2-9)/(x-6)
(x^2-3x)/(x^4-6x^3+9x^2)=x(x-3)/[x^2(x-3)^2]=1/[x(x-3)]
格式有点乱,〖((1-x)/(3-x))^2/((x^2-6x+9)/(9-x^2 ))〗^ ×1/(x^2-2x+1)=〖((1-x)/(3-x))^2/(〖(X-3)〗^2/(
(3-x分之x-1)平方÷(x平方-6x+9分之9-x平方)平方*x平方-2x+1分之6+2x=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]
原式=(x-1)/(x-3)²-1/(x-3)+2x/(x+3)(x-3)=(x²+2x-3)/(x-3)²(x+3)-(x²-9)/(x-3)²(x
sinx是值域在-1到1的有界函数,所以在x趋于无穷大的时候,原极限=lim(x趋于无穷大)2x/(-3x)=-2/3
(X的平方+9x)/(x的平方+3x)+(x的平方-9)/(x的平方+6x+9)=x(x+9)/x(x+3)+(x+3)(x-3)/(x+3)²=(x+9)/(x+3)+(x-3)/(x+3
x趋向于0时,sin(1/x)并不趋向于0,由换元法可知,t趋向于0时,sint~t,当t不趋向于0时,就没有这个等价无穷小.因为y=sin(1/x)是有界函数,所以易知lim(x→0)x^2sin(
x的平方-6x+9/9-x的平方÷2x-6/x的平方+3x{(x-3)²/[(3-x)(3+x)]}÷{2(x-3)/[x(x+3)]}=[(3-x)/(3+x)]÷{2(x-3)/[x(x
1.(x²+x)/(x²-1)=x(x+1)/[(x+1)(x-1)]=x/(x-1)2.(x²-9)/(x²-6x+9)=(x+3)(x-3)/(x-3)
第一题答案为x,当n趋近于无穷时,sin(x/2^n)等价于x/2^n,故为X第二题写的不太明白,没法做.
(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(
当x→0-时limsin|x|/x=-limsinx/x=-1当x→0+时limsin|x|/x=limsinx/x=1所以极限不存在
(4x+20)(x的平方-6x+9)/(3x-x的平方)(x的平方+2x-15)=4(x+5)(x-3)²/3(3-x)(x-3)(x+5)=-4/3
(x的平方+9)的平方-36x的平方=(x^2+6x+9)(x^2-6x+9)=(x+3)^2(x-3)^2
(x²-6x+9)/(x+1)÷(x²-9)/(x²+x)=[(x-3)²/(x+1)]×[x(x+1)/(x+3)(x-3)]=x(x-3)/(x+3)x的平
4-4x分之9x-9=9(x-1)/4(1-x)=-9/4
1,整理得到y=(4+x)/(1+x)=1+3/(1+x),所以要使y为整数,1+x是3的约数,1,3,对应x为0,2,带入求y即可.2,整理为2(x-y)方+3(y-2)方+1,要使最小,x=y=2
原式=[(2X-3)/X-X/X]/[(X+3)(X-3)/X]=[(2X-3-X)/X]/[(X+3)(X-3)/X]=[(X-3)/X]×[X/(X+3)(X-3)]=X(X-3)/[X(X+3)