log的3次方乘以9
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 09:02:02
![log的3次方乘以9](/uploads/image/f/672911-71-1.jpg?t=log%E7%9A%843%E6%AC%A1%E6%96%B9%E4%B9%98%E4%BB%A59)
log底数2真数25换底后是:(lg25)/(lg2)依次类推就是lg25/lg2*lg4/lg3*lg9/lg5整理一下得(lg25*lg4*lg9)/(lg2*lg3*lg5)在化简得(2lg5*
2^[1-log(4)5]+log(√2)4+log(3)1/9=2^[1-log(4)5]+log(√2)(√2)^4+log(3)3^(-2)=2^[1-log(4)5]+4-2=2^log(4)
就是解不等式咯.里面的那条式大于零.其他会解了吧
2^[2+log(2)3]+3^[5-log(3)9]=2^[log(2)4+log(2)3]+3^[log(3)243-log(3)9]=2^[log(2)(4×3)]+3^[log(3)(243÷
原式=5*3^4+4*3^4+3^4=3^4(5+4+1)81*10=810
0.5
log8(9)=lg9/lg8=2lg3/(3lg2)=(2/3)log2(3)
log8(9)=2/3log2(3)log3(32)=5log3(2)2/3log2(3)*5log3(2)=10/3
答:log以2为底5的负2次方的对数乘以log以为底2的负3次方乘以log以五为底3的负2次方={log2[5^(-2)]}×{log3[2^(-3)]}×{log5[3^(-2)]}=[-2log2
log2(25)*log3(1/16)*log5(1/9)=16log2(5)*log3(2)*log5(3)你是实在不会换低.你可以记住这个公式loga(b)=lna/lnb其实换低公式就是这样来的
=2log23×3log32=6log23×log32=6
log(2)1/25乘以log(3)1/8乘以log(5)1/9=-2log(2)5*3log(3)2*log(5)3=-12*ln5/ln2*ln2/ln3*ln3/ln5=-12
log(3)15乘以log(5)15=(1+(log(3)5)乘以(1+log(5)3)=2+log(3)5+log(5)3
9乘以log以3为底5的对数=9×[(log5)÷(log3)]=9×[0.69897000433601880478626110527551÷0.477121254719662437295027903
log2(25)*log3(4)*log5(9)=lg25/lg2*lg4/lg3*lg9/lg5(换底公式)=lg5^2/lg2*lg2^2/lg3*lg3^2/lg5=2lg5/lg2*2lg2/
log以2为底25乘以log以3为底2√2乘以log以5为底9=2log25×(3/2)log32×2log53=6log25×log32×(log23/log25)=6(log25×1/log52)
答案:2009令x=log以3为底2^k的对数则,原式f(3^x)=x/4*log以2为底3的对数+250就变成f[3^(log以3为底2^k的对数)]=log以3为底2^k的对数/4*log以2为底
0.125的49次方乘以4的49次方减去9的999次方乘以3分之一的999次方=(0.125x4)的49次方-(9x1/3)的999次方=(1/2)的49次方-3的999次方
您好:log(3)2-log(3)32/9+log(3)16-5的2log(5)3次方=log(3)(2x16÷32/9)-2x3=l0g(3)9-6=2-6=-4如果本题有什么不明白可以追问,如果满