若分式x²-x-6 x²-3x 2 的值喂0
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![若分式x²-x-6 x²-3x 2 的值喂0](/uploads/image/f/6973260-60-0.jpg?t=%E8%8B%A5%E5%88%86%E5%BC%8Fx%C2%B2-x-6+x%C2%B2-3x+2+%E7%9A%84%E5%80%BC%E5%96%820)
1/(x-3)-6/(x2-9)-(x-1)/(6+2x)=1/(x-3)-6/[(x+3)(x-3)]-(x-1)/[2(x+3)]=[2x+6-6*2-(x-1)*(x-3)]/[2(x+3)(x
X=-6x=-6(X/(X-2))*((X-6)/(X-3))=1-
x+1/x=3(x+1/x)^2=3^2=9x^2+1/x^2+2=9x^2+1/x^2=7
不是,x和x约掉了,就剩下2了,但要保证x不为零~加油!
B=(3-x+x+3)/[-(x+3)(x-3)=-6/(x²-9)选3
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以:(x+1)(x+2)(x-3)得:(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
等式两边同时乘以(x+3)(x-2)(x+2)就可以去分母了
∵当△=b2-4ac<0时,x2+4x+m=0无解,即42-4m<0,解得m>4,∴当m>4时,不论x取何实数,分式总有意义.故答案为m>4.
(2x^2-4x-3)/(x^2-2x-1)-3=0{(2x^2-4x-3)-3(x^2-2x-1)}/(x^2-2x-1)-=0{-x^2+2x}/(x^2-2x-1)=0-x(x-2)/(x^2-
x+6/2x-3=3/1jie:原式可化为:(X+6)*1=(2X-3)*3X+6=6X-95X=15X=3检验:当X=3时,2X-3不等于0所以:原分式方程的解为X=31-X/2=1-X/3原式可化
(X/(X-2))*((X-6)/(X-3))=1->X(X-6)=(X-2)(X-3)->X^2-6X=X^2-5X+6->X=-6
∵x2-9=0,∴x=±3,当x=3时,x2-4x+3=0,∴x=3不满足条件.当x=-3时,x2-4x+3≠0,∴当x=-3时分式的值是0.故选C.
2(x^2+1)/(x+1)+6(x+1)/(x^2+1)=72(x^2+1)^2+6(x+1)^2=7(x+1)(x^2+1)2(x^2+1)^2-7(x+1)(x^2+1)+6(x+1)^2=0[
x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/
方法分母先提取x,然后消掉.再通分,去分母,然后解x.是不是我算错了.貌似无解再问:X²+3x分之1再答:等我一下。我把算式用图画写给你再问:好像是无解再答:嗯嗯,这类题目的方法就是这样了。
对分母x^4+x^2+1进行因式分x^4+x^2+1=x^4+2x^2+1-x^2=(x^2+1)^2-x^2=(x^2+x+1)(x^2-x+1),又因为x^2-3x+1=0,所以x^2=3x-1.
方程两边同时乘以(x2-1),得:2(x-1)+3(x+1)=6,解得:x=1,检验:当x=1时,x2-1=0,∴x=1是增根,∴原分式方程无解.
1.当x=任意实数时,分式x-7/x2+1有意义2.当x≠-1且x≠3值时,分式x/(x+1)(x-3)有意义3..当x=x<7/3且x≠0值时,分式x²/3x-7值为负数3x-7<0x<7
1.两边乘X(X-2)X=3(X-2)X=3X-6X=3分式方程要检验经检验,X=3是方程的解2.原式=[-(X-3)²/(X+3)(X-3)]÷[2(X-3)/X(X+3)]=[-(X-3
6x2+12x+10x2+2x+2=6(x2+2x+2)−2x2+2x+2=6−2x2+2x+2=6−2(x+1)2+1∵(x+1)2≥0,∴(x+1)2+1≥1,即1(x+1)2+1≤1,−2(x+