计算 :(-4x分之x^2y)除以(2ax^分之-y)

①-x+2y分之x-y除以x的平方+4xy+4y的平方分之x的平方-y的平方=-(x-y)/(x+2y)÷(x^2-y^2)/(x^2+4xy+4y^2)=-(x-y)/(x+2y)×(x^2+4xy

(1)[1+(x-2分之1)]除以(2x-4)分之(x^2-1)=(x-1)/(x-2)*2(x-2)/(x+1)(x-1)=2/(x+1)[等于(x+1)分之2](2)[(x-y)^2+3(x^2-

=(2X/3Y)*(3X/4Y)*(4/xy)=(2x*3x*4)/(3y*4y*xy)=2x/(y^3)

(3x²/4y)²×(2y/3x)+(x²/2y²)÷(2y²/x)=(9x⁴/16y²)×(2y/3x)+(x²/2

(3x/y)*(1/4x)*(y/4x)=3/16x

解:化简得{21x-5y=-104①14x-3y=4②①x13得-273x-65y=-1352③②x5得70x-65y=4④④-③得x=4将x=4带入②中得y=4∴原方程组的解是{x=4y=4我也是刚

1.计算：x-y分之x+y+y-3分之2x=(x+y)/(x-y)+2x/(y-3)=((x+y)(y-3)+2x(x-y))/(x-y)(y-3)=(xy-3x+y^2-3y+2x^2-2xy)/(

是否这样：√[x+y）/xy²]÷√x（x+y）=√[（x+y）/（x+y）x²y²]=√1/x²y²=1/|x||y|再问：是这样麻烦了~再答：知道

(16x^2y^4+8x^4y^2-2x^2y^2)除(-4x^2y^2)=16x^2y^4除(-4x^2y^2)+8x^4y^2除(-4x^2y^2)-2x^2y^2除(-4x^2y^2)=-4y&

原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/

[3x分之2-（x+y分之2）乘以[3x分之x+（y-x^2-xy）]除以x分之x-y{2/3x-2/(x+y)*[x/3x+(y-x²-xy)]}÷(x-y)/x题目错了吧?再问：{3x分

1.（4x^2-25y^2）/(2x-5y)=(2x+5y)(2x-5y)/(2x-5y)=2x+5y2.(2x^2-2x+1\2)/(x-1\2)=2(x^2-x+1/4)/(x-1/2)=2(x-

13y-4x

[4/(x^2-y^2)+(x+y)/(xy^2-x^2y)]除[(x+2y)(x-y)/(x^2y+2xy^2)=[4/(x-y)(x+y)+(x+y)/xy(y-x)]*xy/(x-y)=[(4x

解(x²-1)/y÷(x+1)/y²=(x-1)(x+1)/y×y²/(x+1)=y(x-1)

2x/(2x-y)+y/(y-2x)=2x/(2x-y)-y/(2x-y)=(2x-y)/(2x-y)=1

原式=[（x+2）/x（x-2）-（x-1）/（x-2）²]÷（4-x）/x=[（x+2）（x-2）/x（x-2）²-x（x-1）/x（x-2）²]÷（4-x）/x=[（

（x^2-y^2）÷（x分之x-y+y^2分之x^2-y^2-x-y分之x+y）=（x^2-y^2）÷（1-y+x^2/y^2-y^2-x-x/y+y）=（x^2-y^2）÷（1-y+y+x^2/y^

x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²

①(4x²/3y²)×(y/2x³)=2/3xy②(3ab²/2c²d²)÷(-3a²b²/4cd)=(3ab²