搜搜考试网计算m加3分之m减9减m的平方分之6除以m减3分之2
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解;（m/（m-n)²+（n/(n-m)²=m²/(m-n)²+n²/(n-m)²=m²/(m-n)²+n²/
(m²-3m)/(9-m²)=m(m-3)/(3+m)(3-m)=-m/(m+3);您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,如果满意
m^2-3m+1=0m-3+1/m=0m+1/m=31)m^2+1/m^2=(m+1/m)^2-2=3^2-2=72)m^4+1/m^4=(m^2+1/m^2)-2=7^2-2=47
m+1/m=3平方m²+2+1/m²=9m²+1/m²=7(m-1/m)²=m²-2+1/m²=7-2=5
原分式=(m²-m)/(m²-3m+2)=[m(m-1)]/[(m-2)(m-1)]分子、分母同时约去(m-1)=m/(m-2)
m^2-3m+1=0m-3+1/m=0m+1/m=3(m+1/m)^2=9m^2+2+1/m^2=9m^2+1/m^2=7
解题思路：利用分式的运算求解。解题过程：过程请见图片。最终答案：略
m^2-5m-1=0m^2=5m+1原式=10m+2-5m+1/(5m+1)=5m+2+1/(5m+1)=(25m^2+15m+3)/(5m+1)=(125m+25+15m+3)/(5m+1)=(14
依题意得：原式化简为=m平方/（m平方-n平方）又因为3m=2n,所以代入化简后的式子,结果为-4/5
a的平方减6ab加9倍b的平方等于2分之3a+2分之9b+2分之1m左边等于（a-3b）²右边等于（3a+9b+m）/2两边同时乘以2则2（a-3b）²=3a+9b+m所以m=2（
2-4ac＜0再答：无解，m为任意实数
置换法.m-5m-1=0m-5m=1m-1=5m因为m≠0,两边同时除以m得m-1/m=5m+1/m=(m-1/m)+2m*1/m=25+2=27所以2m-5m+1/m=m-5m+m+1/m=1+27
m-1/m=4两边平方得到m^2+1/m^2-2=16m^2+1/m^2=18
原式=m^3-m-1=2根号3-1
m/（x²-9）+2/（x+3）=1/（x-3）同乘以x²-9得m+2（x-3）=（x+3）m=-x+9当x=±3时,原方程无意义所以方程无解时m=6,或者m=12
写错了吧应该是(m²-3m)/(9-m²)=-m(m-3)/(m+3)(m-3)=-m/(m+3)
[m/(m+3)-6/(m^2-9)]÷[2/(m-3)]=[m/(m+3)-6/(m+3)(m-3)]×[(m-3)/2]={[m(m-3)-6]/[(m+3)(m-3)]}×[(m-3)/2]=(
=12/(m+3)(m-3)-2/(m-3)+1/(m+3)=12/(m+3)(m-3)-2(m+3)/(m+3)(m-3)+(m-3)/(m+3)(m-3)=(12-2m-6+m-3)/(m+3)(
=12/(m+3)(m-3)-2/(m-3)=12/(m+3)(m-3)-2(m+3)/(m+3)(m-3)=(12-2m-6)/(m+3)(m-3)=-2(m-3)/(m+3)(m-3)=-2/(m