随机生成10个10以内整数,存入数组a[10]并输出

importjava.io.BufferedWriter;importjava.io.File;importjava.io.FileWriter;importjava.io.IOException;p

我已经上机验证过了,正确.思路：产生80个随机数,把这80个随机数由小到大排序,然后从第1个到第80个的顺序挑选偶数,赋值给字符串s1,够10个换行.再从第80个到第1个的顺序挑选奇数,赋值给字符串s

Dimk%Dima%(1To10)PrivateSubCommand1_Click()Fori=1To10Randomizea(i)=Int(Rnd*100+1)NextPrint"a数组:"k=1F

Dimy%,x%Fori=1To10x=Int(Rnd*100)'[0,99]Printx;Ifi=1Theny=xElseIfy>xTheny=xEndIfNextiPrint"最小值";x如果是N

PrivateSubCommand1_Click()Dima(1To2,1To5)AsInteger,i,j,k,fAsBooleanRandomizeFori=1To2Forj=1To5a(i,j)

Randomize初始化随机数发生器Rnd()获取0~1之间的随机数,乘以90后再加上10,取整后就是10~90之间的了然后挑选出来Mod3=0的数据排序就是了再问：就是mod3=0后不会排序啊再答：

'声明变量dimMin_numasintdimMax_numasintdimSum_numasintdimArr_num(9)asint'赋予初始值Min_num=101Max_num=-1Sum_n

#include#include#include#defineMAX100voidqicksort(int*a,int,int);voidchoosesort(int*a,int,int);voidi

PrivateSubForm_Load()RandomizeDimintRndAsIntegerDimstrRndAsStringDimstrOushuAsStringDimiAsIntegerFor

#include#include#includeintmain(){inti,a[10],m,t=0,s=0;floatn;srand((unsigned)time(NULL));for(i=0;i

#include#include#includeintmain(){inti,a[10],m,t=0,s=0;floatn;srand((unsigned)time(NULL));for(i=0;i

importjava.io.File;importjava.io.FileNotFoundException;importjava.io.FileWriter;importjava.io.IOExce

publicstaticvoidmain(String[]args){int[]numbers=newint[10];intsum=50;Randomrandom=newRandom();for(in

'把所有的与最大值相同的都显示出来PrivateSubForm_Load()Me.AutoRedraw=TrueDima(0To19)AsIntegerDimb(0To19)AsIntegerDimM

用rand()产生随机数,rand()会产生从0到一个很大的数,我记不清了,反正很大.如果想出现100以内的,就用rand()%100.你可以定义三个int型整数,两个表示加或者减的对象,另一个标示加

添加两个控件名字分别为sc、tj的按钮.'定义一个窗体数组变量dima(10)asinteger'生成是个随机数privatesubsc_click()'下面这一句可以得到不同的随机数randomiz

Private Sub Command1_Click()    Cls    Dim r(

importjava.util.Random;importjava.io.*;publicclassTest{publicstaticvoidmain(String[]args)throwsIOExc

importjava.util.Random;importjava.io.*;publicclassTest{publicstaticvoidmain(String[]args)throwsIOExc

dimstr(4,5)asintegerdimnum1(4),num2(5)asinteger'num1行的和,num2列的和fori=0to3num1(i)=0num2(i)=0nextnum2(4