搜搜考试网15*2-5x=23
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/03 15:54:01
是这样的：x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)
2.8+0.3x=415*2-5x=233.4-3x=7x-4.620-6x+4x=100.3x=4-2.830-5x=23-3x-7x=-4.6-3.420-2x=100.3x=1.25x=30-2
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583
x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊
2x+6=5x5x-2x=63x=6x=26x-28=2x6x-2x=284x=28x=78(x-3.6)=0.8x8x-0.8x=28.87.2x=28.8x=415x-110+7x=11015x+
15x=23x-248x=24x=312+5x=3x-82x=-20x=-103(x-3)=9-(x+6)4x=9+9-6=12x=34+x=4x-173x=21x=7
(x-3)/5x=2/1515(x-3)=10x15x-45=10x5x=45x=9
(5X-15)-(2X+3)=X+123x-18=x+122x=30x=15
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=
x²-2x=5x²-2x-5=0x四次方+3x³-12x²-31x-15=x的4次方-2x³-5x²+5x³-10x²-
7X=2X+1515=7X-2X15=5X5X=15X=15/5X=3正确啊
∵(x^4-4x^2+5x-15)/[(x^2+1)(x-2)]=[(x^4+x²-5x²-5)+(5x-10)]/[(x²+1)(x-2)]=[x²(x&su
50％x=2再答：x=4再答：1.2x=2.4再答：x=2再答：1.05x=4.2再答：x=4再答：0.5x=0.2再答：x=0.4再答：请采纳再问：可不可以把式子、过程、答案合并在一起再答：那就是过
=x^2+10x-24+x^2+15x+56-x^2+5x+50=x^2+30x+82=4+60+82=146其实,不化简,直接代入=14*0+9*10+7*8=0+90+56=146也很简单
x^2-2x+1=15(x-1)^2=15x=正负根号15+1x(2x-5)=4x-102x^2-5x-4x+10=02x^2-9x+10=0(2x-5)(x-2)=0x=5/2或x=2x^2+5x+
15-4+5X=2X+35-3X11+5X-2X+3X=356X=35-116X=24X=4