x分之1 Y分之2=2,求代数式-4x 8xy-2y分之4x 3xy 2y
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![x分之1 Y分之2=2,求代数式-4x 8xy-2y分之4x 3xy 2y](/uploads/image/f/900729-9-9.jpg?t=x%E5%88%86%E4%B9%8B1+Y%E5%88%86%E4%B9%8B2%3D2%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F-4x+8xy-2y%E5%88%86%E4%B9%8B4x+3xy+2y)
由条件可得:①2x+y=2②5x+2y=4①×2,得4x+2y=4③②-③,得x=0⑤将⑤代入①,得y=2∴所求代数式=(0+2×2+1)/(2×0-3×2+7)=5/1=5
1/X-1/Y=3分子分母同除以xy=(1/y-2-1/x)/(2/y+3-2/x)=(1*3-2)/(2*3+3)=1/9
再问:(x-6分之5x-4)的平方再答:哦!看错了!嘿嘿!那就是一样的,x-6分之5x-4等于0,x=5分之4.3x+2y=5分之12-6=负5分之18
能把问题说得明白点么是不是二分之x的方加y的方这是一个整体?然后再减xy?
x=1/3y=1/2x-(x+y)+(x+2y)-(x+3y)+...-(x+13y)=6y-13y=-7y=-7/2=-3.5
3x²+xy-2y²=0(x+y)(3x-2y)=0x=-y,或3x=2yy/x=-1,或3/2x/y-y/x-(x²+y²)/(xy)=x/y-y/x-x/y
因为(x-1)2+(y-2)2=0;所以,x=1;y=2;原式=x分之一减去y分之一=1-2014分之一=2014分之2013再问:有两个问题再答:你再检查一下第二问,(-2x3分之1)(-3x4分之
2x-y分之x+y=2,则2x-y=2(x+y)4x-2y分之x+y-4x+4y分之2x-y=2(2x-y)分之x+y-4(x+y)分之2x-y=4(x+y)分之x+y-4(x+y)分之2(x+y)=
2x-y+1的绝对值+(3x+2分之3y)平方=0则2x-y+1=03x+3y/2=0,则2x-y=-1①2x+y=0②①+②,得4x=-1,则x=-1/4①-②,得-2y=-1,则y=-1/2x+y
|2分之5x-y|+y²-10y+25=0|2分之5x-y|+(y-5)²=0∴5x/2-y=0y-5=0∴x=2y=51-x-2y分之x-y×x平方-y平方分之x²-4
x+y分之4x-2y-2x-y分之4x+4y=2(2x-y)/(x+y)-4(x+y)/(2x-y)=2*2-4*(1/2)=4-2=2
解原式=2(x-y)/(x+y)-(x+y)/3(x-y)=6(x-y)(x-y)/[3(x+y)(x-y)]-(x+y)x+y)/[3(x-y)(x+y)]=5(x-y)(x-y)/[(x+y)(x
因为X+2/X-Y=2所以X=2Y+2将X=2Y+2代入X+Y/3(X-Y)-(X-Y)/2(X+Y)=(3Y+2)/3(2Y+2-Y)-(2Y+2-Y)/2(3Y+2)接下来自己算
x+y=10x-y=8/7原式=-7³/8*(x+y)³*(x-y)*4(x+y)²(x-u)²=-343/2*(x+y)^5*(x-y)³=-343
再答:不明白的地方可以追问,望采纳,谢谢
1-8x≥0x≤1/88x-1≥0x≥1/8所以x=1/8y=0+0+1/2=1/2x/y=1/4y/x=4原式=√(1/4+4+2)-√(1/4+4-2)=√25/4-√9/4=5/2-3/2=1
因为x+y/2=3x+4y/5=1,所以x+y=2,3x+4y=5所以解方程组得x=3,带入x+5y+6/3x-y+1,得4/11
(x+y)/2-(x-y)/3=1等式两边同时乘以6,得3(x+y)-2(x-y)=63x+3y-2x+2y=6x+5y=65y=6-xy=(6-x)/5
解题思路:根据已知条件先求得X,Y的值,再化简所求代数式,代入即可。解题过程: