x的三次方加x的平方y减xy的平方减y的三次方-搜答案-搜搜考试网

合并同类项后得x^4+(a+5)x^3-(b+4)x^2+6x-2因为不含x的3次方和2次方项所以a+5=0b+4=0所以a=-5b=-4所以ab=20

x^3-2x^2y^2+xy^3=x(x^2+2xy^2+y^3)很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

x³-y³=(x-y)(x²+xy+y²)所以是乘x-y

x^3y-2x^2y^2+xy^3=x^3y+2x^2y^2+xy^3-4x^2y^2=xy(x^2+2xy+y^2)-4x^2y^2=xy(x+y)^2-4x^2y^2=12×7×7-4×12×12

(x²-xy²+y³)/(x²-y²)不能继续化简

4x的三次方y+4x的平方y的平方+xy的三次方=xy（4x^2+4xy+y^2）=xy(2x+y)^2肯定对望采纳

√（x-4y）=4x-4y=4的2次方x-4y=16（1）（3x+5y）的3次方=-273x+5y=-3（2）（2）-（1）×3得3x+5y-3（x-4y）=-3-16×33x+5y-3x+12y=-

x³－2x²y＋xy²=x(x²－2xy＋y²)=x(x－y)²

X2+Y2-4X-6Y+13=0X2-4X+4+Y2-6Y+9=0（X2-4X+4）+（Y2-6Y+9）=0（x-2）2 +（y-3）2=0所以,x-2=0 x=2y-

x²y-2x²y²+xy³=xy(x-2xy+y²)出题者估计是X的三次方y减2x的平方y的平方加xy的三次方x³y-2x²y&#

x³+x²y+xy²+y³=x²(x+y)+y²(x+y)=(x+y)(x²+y²)

(X-2)的平方加根号Y加三=0x-2=0,y+3=0x=2,y=-3-4y³-(xy-x²)=-4×(-27)-(-6-4)=108+10=128再问：最后一步：108加10=1

先分解因式,后乘法.(X^4-Y^4)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X+Y)(X^2+Y^2)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X^3+X^2Y+XY^2+

原式=x(x²-4y²）-2y(x²-4y²）=(x-2y)(x+2y)(x-2y)=(x+2y)(x-2y)²

由x³-2x²y+xy²-x=x（x²-2xy+y²-1)=x[（x-y）²-1]=x（x-y-1）（x-y+1）.再问：分解因式：-49x

x²y³-2x(4xy³)=x²y³-2x²y³=-x²y³

原式等于(xy)^2(x+y)将x+y=2,xy=4代入,得原式等于16×2=32

x³y-xy³=xy(x²-y²)=xy(x+y)(x-y)

xy(x+y)²-4x³y³=xy[(x+y)²-4x²y²]=xy(x+y+2xy)(x+y-2xy)

x³-y³-x²y+xy²=(x³-y³)-(x²y-xy²)=(x-y)(x²+xy+y²)-xy