x的平方减2x分之x除以
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1楼最后算错了引用一下:1/(x+1)-1/(x²-1)÷(x+1)/(x²-2x+1)=1/(x+1)-1/(x+1)(x-1)×(x-1)(x-1)/(x+1)=1/(x+1)
[(x²-2x)分之(x+2)]÷[(x²-2x)分之(x-4)]=[(x²-2x)分之(x+2)]×[(x-4)分之(x²-2x)]=(x-4)分之(x+2)
原式=(x^2-1)/x÷(x^2+x)/x^2=(x-1)(x+1)/x*x^2/x(x+1)=x-1当x=2时,原式=2-1=1
(1-x)^2/(x^2+4x+4)/(x-1)^2*(x^2+3x+2)/(x-1)=(x+1)/(x+2)(x-1)=(x+1)/(x^2+x-2)再问:是1-x的平方,不是(1-x)的平方再答:
[3x/(x+1)-x/(x-1)]÷(x-2)/(x^2-1)=(2x^2-4x)/(x^2-1)÷(x-2)/(x^2-1)=2x(x-2)/(x-2)=2x
[x的平方-x分之x+1-x的平方-2x+1分之x]除以x分之1=[(x+1)/x(x-1)-x/(x-1)²]×x=(x+1)/(x-1)-x²/(x-1)²=(x
没有问题请采纳,有问题欢迎再追问!
(x的平方-2x)分之(x的平方-4x+4)除以x分之4=[x(x-2)]分之(x-2)²×4分之x=4分之(x-2)
=(x+2)(x-1)/(x-3)×(x-3)²/(x+2)=(x-1)(x-3)=x²-4x+3
x的平方-2x+1分之x²-1+x-2分之2x-x²除以x=(x+1)(x-1)/(x-1)²-x(x-2)/(x-2)÷x=(x+1)/(x-1)-1=(x+1-x+1
[x的平方-x分之x+1-x的平方-2x+1分之x]除以x分之1=[(x+1)/x(x-1)-x/(x-1)²]×x=(x+1)/(x-1)-x²/(x-1)²=(x
[(x-1)/x-(x-2)/(x+1)]÷[(2x^2-x)/(x^2+2x+1)]=[(x-1)(x+1)-x(x-2)]/x(x+1)÷[x(2x-1)/(x+1)^2=(2x-1)/x(x+1
(x的平方-1分之x的平方-2x+1+x分之1)除以x+1分之1=((x-1)^2/(x-1)(x+1)+1/x)*(x+1)=((x-1)/(x+1)+1/x)*(x+1)=(x-1)+(x+1)/
分子分母同乘以4.再一化简
原式=[(x+y)/(x-y)]^2*[2(x-y)/5(x+y)-[X/(x^2y^2)]/[x/(x+y)]=2/5-[x/(x^2y^2)]*[(X+y)/x]=2/5-(x^2y^2)/(x+
2x分之x的平方-4x+4除以x平方分之x的平方-2x+1等于2分之x,当x=0或2时,分式无意义
[(x²-4x+4)/(2x)]÷[(x²-2x+1)/x²]=[(x-2)²/(2x)]/[(x-1)²/x²]=(x-2)²x
∵x²+X-1=0∴x²+x=1x²=1-xX(1减1-X分之2)除以(X+1)减X的平方-2X+1分之X(X的平方-1)=x[1-2/(1-x)]÷(x+1)-x(x&
再问:那个题不是这样的。是再答:再问:带入麻烦写一下,谢谢再答:什么叫合适的代入,最大值最小值?还是别的再问:然后从-根号下5小于x小于根号下5中选择一个合适的带入再答:可以x=21/(x+2)=1/
x的平方-1分之x除以x的平方分之x的平方=x²-(x/1)/(x²/x²)=x²-(x)/1=x²-x