y=-6sin
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sin(x+y)sin(x-y)=-1/2(cos(x+y+x-y)—cos(x+y-x+y))=-1/2(cos2x—cos2y)=-1/2(1-2(sinx)^2-1+2(siny)^2)=(si
y=sin(sinx)y‘=cos(sinx)*(sinx)'=cos(sinx)*cosx
y=(sinxcospi/6+cosxsinpi/6)(sinxcospi/6-cosxsinpi/6)=(sinxcospi/6)^2-(cosxsinpi/6)^2=3/4*(sinx)^2-1/
y=sinx先向左平移π/6,得y=sin(x+π/6)然后,纵坐标不变,横坐标变为原来的1/2,得y=sin(2x+π/6)最后,向上平移3/2,得y=sin(2x+π/6)+3/2
合并同类项么,很简单的只要你愿意去做左边=cos*x(cos*y+sin*y)+sin*x(cos*y+sin*y)=cos*x+sin*x=1=右边
左边=(sinxcosy+cosxsiny)(sinxcosy-cosxsiny)=sin²xcos²y-cos²xsin²y=sin²x(1-sin
dy/dx相当于对x进行求导:dy/dx=y'=2x*cos[sin(x^2)]*cos(x^2)由于:sinx=cosx,sin(x^2)=2x*cos(x^2)
y'sin(y/x)-y/x*sin(y/x)+1=0令y/x=u,则y'=u+xu'所以(u+xu')sinu-usinu+1=0xu'sinu+1=0-sinudu=dx/x两边积分:cosu=l
因为是1/3由1/3->1是缩短根据左加右减的原则选A
sinx+siny+sinz-sin(x+y+z)=4sin[(x+y)/2]sin[(x+z)/2]sin[(y+z)/2]sinx+siny+sinz-sin(x+y+z)=2sin[(x+y)/
∵0≤x≤π2,∴π6≤x+π6≤2π3;∴当x+π6=π2时,函数取得最大值是y=sin(x+π6)=1;当x+π6=π6时,函数取得最小值是y=sin(x+π6)=12;∴函数y=sin(x+π6
-2k=cos2x-cos2y=[2(cosx)^2-1]-[2(cosy)^2-1]=2[(cosx)^2-(cosy)^2]cos^2x-cos^2y=-k
(1)当y=C时,sin[(x+C)/2]=sin[(x-C)/2]移项,和差化积有2cos{[(x+C)/2+(x-C)/2]/2}sin{[(x+C)/2-(x-C)/2]/2}=0,即cos(x
通过复合函数求导,可以得到y'=cos(3x-π/6)*3=3cos(3x-π/6)欢迎追问~
对的,还可以:1.将x坐标向左平移π/6个单位2.将x坐标扩大两倍,y坐标不变
y=sin(2x+π/3)=sin[π/2+(2x-π/6)]=cos(2x-π/6)
y=sin(x+π/6)sin(x-π/6)+acosx=(3/4)(sinx)^2-(1/4)(cosx)^2+acosx=-(cosx)^2+acosx+3/4=-(cosx-a/2)^2+a^2
任何正弦函数,只要系数是1,值域就是[-1,1]