y=6y x-xy^2的微分方程解

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y=6y x-xy^2的微分方程解
已知x+y=8,xy=6,求yx+xy

yx+xy=xyx+xyy=xy(x+y)xy,∵x+y=8,xy=6,∴原式=6×86=463.

求微分方程y'=(1+y^2)/xy的通解

dy/dx=(1+y^2)/(xy)[y/(1+y^2)]dy=dx/x两边积分得1/2[ln(1+y^2)]+c1=ln|x|+c2,c1,c2为任意常数两边都以e为底数得1+y^2=cx^2,c为

求方程(y^2+xy^2)dx+(x^2-yx^2)dy=0的通解

∵(y^2+xy^2)dx+(x^2-yx^2)dy=0==>y²(1+x)dx+x²(1-y)dy=0==>[(y-1)/y²]dy=[(1+x)/x²]dx

dx/(x^2-xy+y^2)=dy/(2y^2-xy)的微分方程

结果当然可以写成:|(y-2x)^3=C(y-x)^2,C为待定常数,解曲线为下面是具体求解过程:

实数x、y、z满足x=6-3yx+3y-2xy+2z

x=6-3y               &nbs

已知:y=1−8x+8x−1+12,则代数式xy+yx+2-xy+yx−2的值为(  )

∵1-8x≥0,8x-1≥0,∴x=18,y=12,∴代数式xy+yx+2-xy+yx−2=14+4+2-14+4−2=52-32=1.故选:B.

xy-3xy+2yx-yx

=xy-3xy+2xy-xy=-xy

求微分方程的通解x^2y''-4xy'+6y=x

设x=e^t则d^2y/dt^2-5dy/dt+6y=e^ty=C1*e^(3t)+C2*e^(2t)+1/2e^t=C1*x^3+C2*x^2+x/2再问:设x=e^t则d^2y/dt^2-5dy/

xy'+y-2y^3=0微分方程的解?

伯努利方程xy'+y=2y^3->x/y^3*y'+1/y^2=2令1/y^2=t-x/2*dt/dx+t=2解这个一阶方程得(2x^(-2)+c)*x^2

先化简,再求值: 3-2xy+3yx的平方+6xy-4x的平方y,其中x=-1,y=-2

3-2xy+3yx²+6xy-4x²y=3+4xy-x²y=3+1x2+(-1)²x2=3+2+2=7

xy+yx=10x,y是多少

xy+yx=10x+y+10y+x=11x+11y=100+x10x=100-11yx=10-1.1y所以y只能是0

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

已知x+y=2,xy=-5,则yx+xy

yx+xy=x2+y2xy=(x+y)2-2xyxy当x+y=2,xy=-5时,原式=22-2×(-5)-5=-145.故答案为-145.

求方程dy/dx=(1+y^2)/(xy+yx^3)的解.

dy/dx=(1+y^2)/[xy(1+x^2)]y/(1+y^2)dy=dx/[x(1+x^2)]2y/(1+y^2)dy=2xdx[x^2(1+x^2)]d(y^2)/(1+y^2)=d(x^2)

微分方程xy'+y=x^2的通解

xy'+y=x^2(xy)'=x^2xy=x^3/3+Cy=x^2/3+C/x

求微分方程(y^2+xy^2)dx-(x^2+yx^2)dy=0,满足初始条件(y/x=1)=-1的特解

再问:亲。还有几道提问的帮忙看看吧。谢谢再问:帮忙看一下好吗。谢谢。求下列可分离变量的微分方程的通xy'-ylny=0

已知xy满足x^2+y^2+4/5=2x+y 求代数式yx/x+y的值

你抄错题了吧X2+Y2+5/4=2X+Y移项,得(X-1)2+(Y-1/2)2=0X=1,Y=1/2

求微分方程xy'-2y=5x的通解,

再问:多谢!!!

求微分方程的通解.x^2 y"+xy'=1

令f(x)=x*y'f'=y'+xy''xf'=xy'+x^2y''=1f'=1/xf=lnx+c1xy'=lnx+c1y'=lnx(1/x)+c1/xy=1/2*(lnx)^2+c1*lnx+c2再