(1 x)³ (1 x)四次方 ... (1 x)n 2次方的展开式-搜答案-搜搜考试网

(x²＋1)/x＝根号5x²＋1是分子吧分子分母同除以xx+1/x=根号5(x+1/x)²=5x²+1/x²=3(x四次方＋x二次方＋1)/(x四次方

∵(x^2)/(x^4+1)=1/3∴x^4+1=3x^2∴(x^4)/(x^8+x^4+1)=(x^4)/[(x^4+1)^2-x^4]=(x^4)/[(3x^2)^2-x^4]=(x^4)/(9x

∵x²+x+1=0两边除以x可得x+1+1/x=0x+1/x=-1两边平方可得x²+1/x²+2=1x²+1/x²=-1两边再平方可得x^4+1/x^

x五次方-x四次方+x三次方-x²+x-1=x³（x²-x+1)-(x²-x+1)=(x³-1)（x²-x+1）=(x-1)(x²

5X²-2=（√5x+√2)(√5x-√2)x四次方-4x²+4=(x²-2)²=(x+√2)²(x-√2)²x四次方+2x²-8

x^4+x^3+x^2-1=x^3(x+1)+(x-1)(x+1)=(x^3+x-1)(x+1)

原式＝x^8-x^6-10x^4-x^2+1+10x^4=x^8-x^6-x^2+1=x^6(x^2-1)-(x^2-1)=(x^6-1)(x^2-1)=(x^3+1)(x^3-1)(x+1)(x-1

x^8+x^4+1=x^8+2x^4+1-x^4=(x^4+1)^2-(x^2)^2=(x^4+x^2+1)(x^4-x^2+1)=[(x^4+2x^2+1)-(x^2)](x^4-x^2+1)=(x

x^4-7x^2+1=x^4+2x^2+1-9x^2=(x^2+1)^2-(3x)^2=(x^2+3x+1)(x^2-3x+1)

5x四次方+3x平方y-10-3平方+x四次方-1=5x四次方+3x平方y-10-9+x四次方-1=5x四次方+3x平方y+x四次方=x平方(5x平方+3y+x平方)=x平方(6x平方+3y)

4x四次方-4x²+1=(2x²)²-2×2x²+1=(2x²-1)²=[(x√2)+1][(x√2)-1]

x三次方-x+x+1分之1-x四次方=x(x²-1)-(x²+1)(x²-1)/(x+1)=x(x²-1)-(x²+1)(x+1)(x-1)/(x+1

x²+x+1=0x+1+1/x=0x+1/x=-1两边平方得x²+2+1/x²=1x²+1/x²=-1两边平方得x^4+2+1/x^4=1x^4+1/

x^2+3x+1=0x^2+1/x^2=((-3x-1)^1+1)/(-3x-1)=(9x^2+6x+2)/(-3x-1)=(-27x-9+6x+2)/(-3x-1)=7x^4+1/x^4=(x^2+

不能!再答：令m=x的平方，即m的平方+m－1不能因式分解

x^4-11x^2+1=(x^4-2x^2+1)-9x^2=(x^2-1)^2-(3x)^2=(x^2+3x-1)(x^2-3x-1)

x^4+2x+1=x^4-x²+x²+2x+1=x²(x-1)(x+1)+(x+1)²=(x+1)(x³-x²+x+1)

x^5-x^4+x^3-x^2+x-1=x^4(x-1)+x^2(x-1)+(x-1)=(x-1)(x^4+x^2+1)=(x-1)(x^4+2x^2+1-x^2)=(x-1)[(x^2+1)^2-x

原式=x^4+8√3x²+(48-49)=[(x²)²+(2·1·4√3)x²+(4√3)²]-49……（配成完全平方公式）=(x²+4√3

x的四次方-7x²-18=(x^2-9)(x^2+2)=(x-3)(x+3)(x^2+2)7(a+b)²-5(a+b)-2=(7a+7b+2)(a+b-1)8x²-26x