对F(x)=(θ^2)*(2θ)*(1-θ)*(θ^2)*(1-2θ)求导
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/08/02 21:00:30
对F(x)=(θ^2)*(2θ)*(1-θ)*(θ^2)*(1-2θ)求导
![对F(x)=(θ^2)*(2θ)*(1-θ)*(θ^2)*(1-2θ)求导](/uploads/image/z/15201226-10-6.jpg?t=%E5%AF%B9F%28x%29%3D%28%CE%B8%5E2%29%2A%282%CE%B8%29%2A%281-%CE%B8%29%2A%28%CE%B8%5E2%29%2A%281-2%CE%B8%29%E6%B1%82%E5%AF%BC)
F(x)=(2*θ^5)*(1-θ)*(1-2θ)=(10*θ^4)*(1-θ)*(1-2θ)-(2*θ^5)(1-2θ)-2(2*θ^5)*(1-θ)
=(10*θ^4)*(1-θ)*(1-2θ)-(2*θ^5)(3-4θ)
再问: ��F(x)=ln[(��^2)*(2��)*(1-��)*(��^2)*(1-2��)]��~~ ��Ŀ�����~~
再答: F��(x)=1/[(2��^5)(1-��)*(1-2��)]*((10*��^4)*(1-��)*(1-2��)-(2*��^5)(3-4��))
再问: ��F����x��=0,��=??
再答:![](http://img.wesiedu.com/upload/c/dd/cddc033f505e2e038c115e0bbb9b843a.jpg)
再答: ��֪ͨ�����߶���Ļش�������ۣ����Ե�
=(10*θ^4)*(1-θ)*(1-2θ)-(2*θ^5)(3-4θ)
再问: ��F(x)=ln[(��^2)*(2��)*(1-��)*(��^2)*(1-2��)]��~~ ��Ŀ�����~~
再答: F��(x)=1/[(2��^5)(1-��)*(1-2��)]*((10*��^4)*(1-��)*(1-2��)-(2*��^5)(3-4��))
再问: ��F����x��=0,��=??
再答:
![](http://img.wesiedu.com/upload/c/dd/cddc033f505e2e038c115e0bbb9b843a.jpg)
再答: ��֪ͨ�����߶���Ļش�������ۣ����Ե�