#include #include main() {double a,b,c,q,w,e; q=((-b)+sqrt(b
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#include #include main() {double a,b,c,q,w,e; q=((-b)+sqrt(b*b-4*a*c))/(2*a); w=
#include
#include
main()
{double a,b,c,q,w,e;
q=((-b)+sqrt(b*b-4*a*c))/(2*a);
w=((-b)-sqrt(b*b-4*a*c))/(2*a);
e=(-b)/(2*a);
scanf("%lf%lf%lf",&a,&b,&c);
if(b*b-4*a*c>0)
{printf("2解");printf("q=%lf,w=%lf\n",q,w);}
else if(b*b-4*a*c==0)
{printf("1解");printf("e=%lf\n",e);}
else if(b*b-4*a*c
#include
#include
main()
{double a,b,c,q,w,e;
q=((-b)+sqrt(b*b-4*a*c))/(2*a);
w=((-b)-sqrt(b*b-4*a*c))/(2*a);
e=(-b)/(2*a);
scanf("%lf%lf%lf",&a,&b,&c);
if(b*b-4*a*c>0)
{printf("2解");printf("q=%lf,w=%lf\n",q,w);}
else if(b*b-4*a*c==0)
{printf("1解");printf("e=%lf\n",e);}
else if(b*b-4*a*c
![#include #include main() {double a,b,c,q,w,e; q=((-b)+sqrt(b](/uploads/image/z/15236651-11-1.jpg?t=%23include+%23include+main%28%29+%7Bdouble+a%2Cb%2Cc%2Cq%2Cw%2Ce%3B+q%3D%28%28-b%29%2Bsqrt%28b)
计算过程要放在输入值之后,scanf("%lf%lf%lf",&a,&b,&c);这句位置放到q=((-b)+sqrt(b*b-4*a*c))/(2*a);之前去,不然值还没输入,你怎么计算结果?
#include #include main() { char p[20]={'a','b','c','d'},q[]=
#include main() { double a,b,c,d,e; scantf("lf%lf%lf%",a,b,c
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