(x²-2x)²+3(x²-2x)-4=0 ..
4x²-{-3x²-[5x-x²-(2x²-x)]+4x},其中x=½
已知f(x)={x/2,x>=0 -x²+3x,x=0
3x⁷*x⁴+2x*x²*x⁴-4x⁵*(-x)²
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
(x-2)²=(2x-3)² x²-4x=0 3x(x+1)=3x+3 x²-2
x²+3x-2=0,x²-6x-6=0,3x²-4x-1=0,3x²+10x+3
0.3x²+x=0.8 x²+3=2√3x x²+2x-2=0 3x²+4x-7
3x²-(x-2)=0 (2x-1)(x+3)=4 x²-3x-4=0 x²-3x+18=
先化简,再求值(3x/x-2+x/x+2)/(x/x²-4),其中x=-3
解方程:x(6-x)-2x(x+1)-(x^3-3x^4)/x²=4
(X-1)(X-2)=70,(3-X)²+2X(X-1)=0,-3X²-4X+4=0,(3-X)
2x(x-1)=0 x²+4=4x (x-3)(x+1)=0 x²-3x+1=0