x+y+z=0 4x+2y+z=3 9x+3y+z=6 怎么解

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, 请问怎么由2x-3y+z=0 ,3x-2y-6z=0 得到x=3z,y=4z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6} 解方程{3x -y+z=4 2x+3y-z=12 x+y+z=6 解方程组：x+y+z=4,x+y+2z=5,3x+y-z=6 解方程一;{x+y-z=6,x-3y+2z=1,3x+2y-z=-7.②{3x+4z=7,2x+3y+z=9,5x-9y 解方程组2x+y-3z=1,x-2y+z=6,3x-y+2z=9求x,y,z的值 已知方程组4x-y+3z=0 2x+y+6z=0且xyz不等于0,则x/y+y/z+z/x是多少 4x-3y-6z=0,x+2y-7z=0是一个方程组,那么x-y+z/x+y+z的值等于 已知有理数x、y、z满足条件|x-z-2|+(3x-6y-7)^2+|3y+3z-4|=0,求x、y、z ①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-