求极限limx→e (lnx-1)/x-e.
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求极限limx→e (lnx-1)/x-e.
答案是1/e. 洛比达没学过><!
![](http://img.wesiedu.com/upload/9/fe/9fe126970aa7af8e6c5183a6651c2a65.jpg)
答案是1/e. 洛比达没学过><!
![](http://img.wesiedu.com/upload/9/fe/9fe126970aa7af8e6c5183a6651c2a65.jpg)
![求极限limx→e (lnx-1)/x-e.](/uploads/image/z/15412413-21-3.jpg?t=%E6%B1%82%E6%9E%81%E9%99%90limx%E2%86%92e+%28lnx-1%29%2Fx-e.)
lim(x->e) (lnx-1)/(x-e) (0/0)
= lim(x->e) (1/x)/1
=1/e
or
expands lnx about e
lnx = lne +(x-e)/e + (x-e)^2/e^2+...
= 1+(x-e)/e + (x-e)^2/e^2+...
(lnx-1)/(x-e)
= [ 1+(x-e)/e + (x-e)^2/e^2+...- 1] /(x-e)
= ((x-e)/e + (x-e)^2/e^2+.)/(x-e)
= 1/e + (x-e)/e^2 + (x-e)^2/e^3 +...
lim(x->e)(lnx-1)/(x-e)
=lim(x->e)[1/e + (x-e)/e^2 + (x-e)^2/e^3 +...]
=1/e
= lim(x->e) (1/x)/1
=1/e
or
expands lnx about e
lnx = lne +(x-e)/e + (x-e)^2/e^2+...
= 1+(x-e)/e + (x-e)^2/e^2+...
(lnx-1)/(x-e)
= [ 1+(x-e)/e + (x-e)^2/e^2+...- 1] /(x-e)
= ((x-e)/e + (x-e)^2/e^2+.)/(x-e)
= 1/e + (x-e)/e^2 + (x-e)^2/e^3 +...
lim(x->e)(lnx-1)/(x-e)
=lim(x->e)[1/e + (x-e)/e^2 + (x-e)^2/e^3 +...]
=1/e
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