搜搜考试网A three-digit number is the product of four prime numbers.Gi
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A three-digit number is the product of four prime numbers.Given that the three-digit of the number are all prime and different and that the sum of its prime factors is 30 ,find the number.
A three-digit 好像是“三位数”的意思,
一个三位数是四个质数之积,组成三位数的数字全是质数且各不相同,它的质因数的和是30,求这个三位数.
不知对不对,边查字典边译的
质数：2,3,5,7,11,13,17,19,23,29,31……
四个质数之和为30,所以最大只能从29开始,
29+1=30,舍去
23+7=30,——23,2,2,3,积为276,6不是质数,舍去
19+11=30,——19,3,3,5,积为855,8不是质数,舍去
19,2,2,7,积为532,可以
17+13=30,——17,3,5,5,积为1275,舍去
17,3,3,7,积为1071,舍去
13+17=30,——13,3,3,11,积为1287,舍去
13,5,5,7,积为2275,舍去
13,3,7,7,积为1911,舍去
13,2,2,13,积为676,6不是质数,舍去
11+19=30,——11,3,5,11,舍
11,5,7,7,舍
7*4
一个三位数是四个质数之积,组成三位数的数字全是质数且各不相同,它的质因数的和是30,求这个三位数.
不知对不对,边查字典边译的
质数：2,3,5,7,11,13,17,19,23,29,31……
四个质数之和为30,所以最大只能从29开始,
29+1=30,舍去
23+7=30,——23,2,2,3,积为276,6不是质数,舍去
19+11=30,——19,3,3,5,积为855,8不是质数,舍去
19,2,2,7,积为532,可以
17+13=30,——17,3,5,5,积为1275,舍去
17,3,3,7,积为1071,舍去
13+17=30,——13,3,3,11,积为1287,舍去
13,5,5,7,积为2275,舍去
13,3,7,7,积为1911,舍去
13,2,2,13,积为676,6不是质数,舍去
11+19=30,——11,3,5,11,舍
11,5,7,7,舍
7*4
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