6/1*7 - 6/7*13 - 6/13*19 – 6/19*25-…-6/97*103
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/07/15 15:16:10
6/1*7 - 6/7*13 - 6/13*19 – 6/19*25-…-6/97*103
选项 A.433/567 B.532/653 C.522/721 D. 436/673
选项 A.433/567 B.532/653 C.522/721 D. 436/673
6/1*7=1-1/7
6/7*13=1/7-1/13
……
6/97*103=1/97-1/103
6/1*7 - 6/7*13 - 6/13*19 – 6/19*25-…-6/97*103
=1-1/7-(1/7-1/13)-(1/13-1/19)-……-(1/97-1/103)
=1-1/7-1/7+1/103
=5/7+1/103
=522/721
故选C.522/721
6/7*13=1/7-1/13
……
6/97*103=1/97-1/103
6/1*7 - 6/7*13 - 6/13*19 – 6/19*25-…-6/97*103
=1-1/7-(1/7-1/13)-(1/13-1/19)-……-(1/97-1/103)
=1-1/7-1/7+1/103
=5/7+1/103
=522/721
故选C.522/721
6/1*7 - 6/7*13 - 6/13*19 - 6/19*25-…-6/97*103
6/1*7-6/7*13-6/13*19-6/19*25-.-6/97*103变形为(1-1/7)-(1/7-1/13)
计算6/1×7-6/7×13-6/13×19-······-6/97×103.
25*7*6*4 103*23 7/12+3/11+5/12+8/11 15/25*19+19/23*8 8/13+(5
6 6 7 12 19 算32 13 7 13 8 29 算24 17 6 30 23 26 算24 7 19 14 1
19/25+7/12+6/25=?
数列1/2 7/9 13/16 19/13 5/6 ( )
数列题:1/2,7/9,13/16,19/13,5/6,()?2
数列1 7 13 19 25 ...怎么得到通项公式1+6(n-1)的?
-7×(-19分之4)+13×(-19分之4)-6×(-19分之4);
33分之19乘7分之6减7分之6乘13分之5
11/5*6-13/6*7+15/7*8-17/8*9+19/9*10