解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0
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解方程 1. 4(x+3)²=25(x-2)² 2. (1+√2)x²-(1-√2)x=0 (两题都因式分解法)
如题,求步骤简单明了.
如题,求步骤简单明了.
1.4(x+3)²=25(x-2)²
4(x+3)²-25(x-2)²=0
[2(X+3)+5(X-2)][2(X+3)-5(X-2)] =0
[2X+6+5X-10][2X+6-5X+10]=0
(7X-4)(-3X+16)=0
X=4/7或X=16/3;
2.(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
X=0或
X=(1-√2)/(1+√2)
=(1-√2)²/(1-2)
=-(1-√2)²
=-3+2√2
X=0或X=-3+2√2
4(x+3)²-25(x-2)²=0
[2(X+3)+5(X-2)][2(X+3)-5(X-2)] =0
[2X+6+5X-10][2X+6-5X+10]=0
(7X-4)(-3X+16)=0
X=4/7或X=16/3;
2.(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
X=0或
X=(1-√2)/(1+√2)
=(1-√2)²/(1-2)
=-(1-√2)²
=-3+2√2
X=0或X=-3+2√2
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