问几道数学题,英语好的进!
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/07/20 05:14:42
问几道数学题,英语好的进!
1.An integer is chosen at random from 1000 to 9999.Find the probability of choosing an integer having 4 different digits such that the difference between the first and last digits is 2.
2.A={(x,y):3x-y=29} and B={(x,y):2y+5x=52}.Find A∩B
3.It is known that n(A) =10,n(B) =4 and n(∑) =11.Calculate the maximum and minimum values of the following:n(A∪B),n(A∩B),n(A∪B′),
我要的是working and answer,题目看的懂的说。
1.An integer is chosen at random from 1000 to 9999.Find the probability of choosing an integer having 4 different digits such that the difference between the first and last digits is 2.
2.A={(x,y):3x-y=29} and B={(x,y):2y+5x=52}.Find A∩B
3.It is known that n(A) =10,n(B) =4 and n(∑) =11.Calculate the maximum and minimum values of the following:n(A∪B),n(A∩B),n(A∪B′),
我要的是working and answer,题目看的懂的说。
![问几道数学题,英语好的进!](/uploads/image/z/16039727-71-7.jpg?t=%E9%97%AE%E5%87%A0%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%2C%E8%8B%B1%E8%AF%AD%E5%A5%BD%E7%9A%84%E8%BF%9B%21)
1.1000-9999 选出四个数位都不相同且千位,个位相差2的概率
千位各位相差2 只有97,86,75,64,53,42,31,20,13,24,35,46,57,68,79十五种可能 任一组合 十位,百位均有8*7=56种 则共计56*15=840种,概率为840/9000=7/75
2.已知A={(x,y):3x-y=29} and B={(x,y):2y+5x=52}.求 A∩B
A={(x,y):3x-y=29}表示 直线3x-y=29上的点集 ,B={(x,y):2y+5x=52}表示直线2y+5x=52上的点集,A∩B是两直线交点的点集.联立3x-y=29,2y+5x=52即可,得x=10,y=1则A∩B={(10,1)}
3.已知 n(A) =10,n(B) =4 and n(∑) =11,求 n(A∪B),n(A∩B),n(A∪B′)的最大值和最小值
先最大值:maximum values of n(A∪B)=11,maximum values of n(A∩B)=4,maximum values of n(A∪B′)=11
再最小值:minimum values of n(A∪B)=10,minimum values of n(A∩B)=3,minimum values of n(A∪B′)=10
千位各位相差2 只有97,86,75,64,53,42,31,20,13,24,35,46,57,68,79十五种可能 任一组合 十位,百位均有8*7=56种 则共计56*15=840种,概率为840/9000=7/75
2.已知A={(x,y):3x-y=29} and B={(x,y):2y+5x=52}.求 A∩B
A={(x,y):3x-y=29}表示 直线3x-y=29上的点集 ,B={(x,y):2y+5x=52}表示直线2y+5x=52上的点集,A∩B是两直线交点的点集.联立3x-y=29,2y+5x=52即可,得x=10,y=1则A∩B={(10,1)}
3.已知 n(A) =10,n(B) =4 and n(∑) =11,求 n(A∪B),n(A∩B),n(A∪B′)的最大值和最小值
先最大值:maximum values of n(A∪B)=11,maximum values of n(A∩B)=4,maximum values of n(A∪B′)=11
再最小值:minimum values of n(A∪B)=10,minimum values of n(A∩B)=3,minimum values of n(A∪B′)=10