因式分解4(3x^2-x-1)(x^2+2x-3)-(4x^2+x-4)^2谢谢
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/08/02 23:32:43
因式分解4(3x^2-x-1)(x^2+2x-3)-(4x^2+x-4)^2谢谢
![因式分解4(3x^2-x-1)(x^2+2x-3)-(4x^2+x-4)^2谢谢](/uploads/image/z/16213135-31-5.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A34%283x%5E2-x-1%29%28x%5E2%2B2x-3%29-%284x%5E2%2Bx-4%29%5E2%E8%B0%A2%E8%B0%A2)
4(3x^2-x-1)(x^2+2x-3)-(4x^2+x-4)^2
=4(3x^2-x-1)(x^2+2x-3)-[(3x^2-x-1)+(x^2+2x-3)]2^
=4(3x^2-x-1)(x^2+2x-3)-(3x^2-x-1)^2-2(3x^2-x-1)(x^2+2x-3)-(x^2+2x-3)^2
=-(3x^2-x-1)^2+2(3x^2-x-1)(x^2+2x-3)-(x^2+2x-3)^2
=-[(3x^2-x-1)-(x^2+2x-3)]^2
=-(2x^2-3x+2)^2
=4(3x^2-x-1)(x^2+2x-3)-[(3x^2-x-1)+(x^2+2x-3)]2^
=4(3x^2-x-1)(x^2+2x-3)-(3x^2-x-1)^2-2(3x^2-x-1)(x^2+2x-3)-(x^2+2x-3)^2
=-(3x^2-x-1)^2+2(3x^2-x-1)(x^2+2x-3)-(x^2+2x-3)^2
=-[(3x^2-x-1)-(x^2+2x-3)]^2
=-(2x^2-3x+2)^2
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