10-x+10=( )
一:已知f(x)=(10^x-10^-x)/10^x+10^-x.
(2x-2)(x-1)=0 x(x-5)=5x-10
解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8
(X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程)
(x+10)+(X+8)+X\3=36
2x(56-X)-10=30+X
X-0.75X=三分之一X-10(怎么解)
1)x+1/x=3,求x^10+x^5+1/x^5+1/x^10的值
x除(x+10)=0.
解方程:(x+8)/(x+7)+(x+10)/(x+9)=(x+7)/(x+6)+(x+11)/(x+10
(x-6)/(x-5)-(x-7)/(x-6)=(x-9)/(x-8)-(x-10)/(x-9)
计算:1/(x^2-7x+10)+1/(x^2-x-2)+1/(x^2+5x+4)+1/(x^2+11x+28)=( )