分式加减题.(1\X-3)-(1\X^2-9)-(X-1\6-2X)=?(5\X^-2X)-(4\X^2+2X)-(3\
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分式加减题.
(1\X-3)-(1\X^2-9)-(X-1\6-2X)=?
(5\X^-2X)-(4\X^2+2X)-(3\X^2-4)=?
过后追分~
555
(1\X-3)-(1\X^2-9)-(X-1\6-2X)=?
(5\X^-2X)-(4\X^2+2X)-(3\X^2-4)=?
过后追分~
555
![分式加减题.(1\X-3)-(1\X^2-9)-(X-1\6-2X)=?(5\X^-2X)-(4\X^2+2X)-(3\](/uploads/image/z/16532175-39-5.jpg?t=%E5%88%86%E5%BC%8F%E5%8A%A0%E5%87%8F%E9%A2%98.%281%5CX-3%29-%281%5CX%5E2-9%29-%28X-1%5C6-2X%29%3D%3F%285%5CX%5E-2X%29-%284%5CX%5E2%2B2X%29-%283%5C)
1/(x-3)-1/(x^2-9)-(x-1)/(6-2x)
=1/(x-3)-1/((x+3)(x-3))-(x-1)/(2(3-x))
=1/(x-3)-1/((x+3)(x-3))+(x-1)/(2(x-3))分子,分母各乘以2(x-3)(x+3)
=2(x+3)-2+(x-1)(x+3)
=2x+6-2+x^2+2x-3
=x^2+4x+3
=(x+1)(x+3)
第二题看不懂:5\X^-2X
=1/(x-3)-1/((x+3)(x-3))-(x-1)/(2(3-x))
=1/(x-3)-1/((x+3)(x-3))+(x-1)/(2(x-3))分子,分母各乘以2(x-3)(x+3)
=2(x+3)-2+(x-1)(x+3)
=2x+6-2+x^2+2x-3
=x^2+4x+3
=(x+1)(x+3)
第二题看不懂:5\X^-2X
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