设{an}是a1=4的单调递增数列,且满足an+1^2+an^2+16=8（an+1+an）+2an+1an,求an

数列｛an｝满足a1=1,且an=an-1+3n-2,求an 一直数列{an}满足a1=0,an=（an-1 +4）/(2an-1) ,求 an 已知数列an满足:an+1-2an=2^n+1,且a1=2 (1)证明{an/2^n}是等差数列 (2)求数列an的 设数列｛an｝满足an+1/an=n+2/n+1,且a1＝2 设数列{An}的各项都是正数,且A1=1,(An)+1/(An+1)+1=(An+1)/2An,Bn=An平方+An. 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列an满足a1=2,an+1=an²求an 已知数列{an}满足a1=1,an+1=2an+1 1）求证：数列{an+1}为等比数列； 2) 求{an}的通项an 数列an满足a1=2,an+1=4an+9,则an=? 已知数列{an}满足:a1=1,且an-an-1=2n,求(1)a2,a3,a4.(2)求数列{an}的通项an 已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an 已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an