2m+2分之(m+1)²÷m+1分之1×(m+3)² 分之(m+3)(m-3)
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2m+2分之(m+1)²÷m+1分之1×(m+3)² 分之(m+3)(m-3)
![2m+2分之(m+1)²÷m+1分之1×(m+3)² 分之(m+3)(m-3)](/uploads/image/z/16701668-44-8.jpg?t=2m%2B2%E5%88%86%E4%B9%8B%28m%2B1%29%26%23178%3B%C3%B7m%2B1%E5%88%86%E4%B9%8B1%C3%97%28m%2B3%29%26%23178%3B+%E5%88%86%E4%B9%8B%28m%2B3%29%28m-3%29)
(m+1)²/(2m+2)÷1/(m+1)×(m+3)(m-3)/(m+3)²
=(m+1)/2×(m+1)×(m-3)/(m+3)
=(m+1)²(m-3)/[2(m+3)]
再问: 2m+2分之(m+1)²×m+1分之1×(m+3)² 分之(m+3)(m-3)
再答: (m+1)²/(2m+2)×1/(m+1)×(m+3)(m-3)/(m+3)² =1/2×(m-3)/(m+3) =1/2×[1-6/(m+3)] =1/2-3/(m+3)
再问: 1/2怎么得出的?
再答: (m+1)²/(2m+2)×1/(m+1) =(m+1)²/[2(m+1)×(m+1)] =1/2
=(m+1)/2×(m+1)×(m-3)/(m+3)
=(m+1)²(m-3)/[2(m+3)]
再问: 2m+2分之(m+1)²×m+1分之1×(m+3)² 分之(m+3)(m-3)
再答: (m+1)²/(2m+2)×1/(m+1)×(m+3)(m-3)/(m+3)² =1/2×(m-3)/(m+3) =1/2×[1-6/(m+3)] =1/2-3/(m+3)
再问: 1/2怎么得出的?
再答: (m+1)²/(2m+2)×1/(m+1) =(m+1)²/[2(m+1)×(m+1)] =1/2
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试比较2+|m|分之1+|m|与3+|m|分之2+|m|的大小
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先化简,再求值 m平方+m-2分之1+m 除于 m - 2 + m+2分之3
先化简,再求值,m²-m分之m²-2m+1,其中m=92
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