数学题三角函数已知2sin(3π+θ)=cos(π+θ),求2sin^2 θ+3sinθcosθ-cos^2 θ
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数学题三角函数
已知2sin(3π+θ)=cos(π+θ),求2sin^2 θ+3sinθcosθ-cos^2 θ
已知2sin(3π+θ)=cos(π+θ),求2sin^2 θ+3sinθcosθ-cos^2 θ
![数学题三角函数已知2sin(3π+θ)=cos(π+θ),求2sin^2 θ+3sinθcosθ-cos^2 θ](/uploads/image/z/16898020-52-0.jpg?t=%E6%95%B0%E5%AD%A6%E9%A2%98%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E5%B7%B2%E7%9F%A52sin%283%CF%80%2B%CE%B8%29%3Dcos%28%CF%80%2B%CE%B8%29%2C%E6%B1%822sin%5E2+%CE%B8%2B3sin%CE%B8cos%CE%B8-cos%5E2+%CE%B8)
2sin(3π+θ)=cos(π+θ)
2sinθ=cosθ
tanθ=1/2
2sin^2 θ+3sinθcosθ-cos^2 θ 2sin^2 θ+3sinθcosθ-cos^2 θ
___________________________= ____________________________=
1 sin^2 θ +cos^2 θ
分子分母同除以cos^2 θ
2tan^2θ+3tanθ-1
________________ 将tanθ=1/2带入
tan^2θ+1
=4/5
2sinθ=cosθ
tanθ=1/2
2sin^2 θ+3sinθcosθ-cos^2 θ 2sin^2 θ+3sinθcosθ-cos^2 θ
___________________________= ____________________________=
1 sin^2 θ +cos^2 θ
分子分母同除以cos^2 θ
2tan^2θ+3tanθ-1
________________ 将tanθ=1/2带入
tan^2θ+1
=4/5
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